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3 years ago

Use Coulomb's Law to calculate the energy of a copper ion and an oxide ion at their equilibrium ion-pair separation distance.

Chemistry

1 answer:

Tanzania [10]3 years ago

8 0

E= (231 aj/pm) (-2)(2)/77+140 Pm

E= 231 aj (-4)/217

E= -868 aj/ 217

E= -4aj

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A man weighing 48 N climbs 82.0 meter ladder how much work is done

Karolina [17]

Heeeyyyyyyyy........

3 0

3 years ago

How many moles of nitrogen gas are there in 16.8 L of this gas at STP?

sweet-ann [11.9K]

According to Avogadro's Law, same volume of any gas at standard temperature and pressure will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

n = moles = ?
V = Volume = 16.8 L

Solution:
As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

= ( 1 mole × 16.8 L) ÷ 22.4 L

= 0.75 moles

Result:
16.8 L of Nitrogen gas will contain 0.75 moles at standard temperature and pressure.

4 0

3 years ago

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)

Misha Larkins [42]

Moles=volume*concentration
=0.1*.83
=.083 Moles of HC2H3O2
Mole ratio between HC2H3O2 and CO2 is 1:1
This means .083 Moles of CO2

Mass =Moles*Rfm of CO2
=.083*(12+16+16)
=3.7grams

8 0

3 years ago

2. ATO kg bouting ball would require what force to accelerate down an alleyway at a rate of ons?

Mars2501 [29]

Answer:

2. 30N

3. 5,000N

4. 15 kg

5. 2,800 kg

Explanation:

2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?

Notice that I completed the question with the garbled and missing values:

Data:

F = ?

m = 10 kg

a = 3m/s²

Physical principles:

Newton's second law: $F=m\times a$

Solution:

Substitute and compute

$F=10kg\times 3m/s^2=30N$

3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?

Notice that I arranged the typos.

Data:

F = ?

m = ?

a = ?

Physical principles:

Newton's second law: $F=m\times a$

Solution:

Substitute and compute

$F=1,000kg\times5m/s^2=5,000N$

4. What is the mass of a falling rock if it produces a force of 147 N?

Data:

F = 147N

m = ?

a = falling rock

Physical principles:

neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²

Newton's second law: $F=m\times a$

Solution:

Clear m from Newton's second law

$m=\dfrac{F}{a}$

Substitute with F = 147 N and a = g = 9.8m/s², and compute

$m=\dfrac{147N}{9.8m/s^2}=15Kg$

5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?

Data:

F= 14,000N

m = ?

a = 5m/s²

Physical principles:

Second Newton's law: $F=m\times a$

Solution:

Clear m from Newton's second law

$m=\dfrac{F}{a}$

Substitute with F = 14,000 N and a = 5m/s², and compute

$m=\dfrac{14,000N}{5m/s^2}=2,800kg$

6 0

3 years ago

Hydrogen (H), oxygen (O), and Nitrogen (N) are all examples of which of the following?

Llana [10]

Answer:

All are correct

Explanation:

This might be a little deceptive. The question shows H, O and N which would designate ELEMENTS.

However, all of these can also be considered compounds and molecules as well. BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.

So it depends on the whether the question is being literal or not.

8 0

2 years ago