Answer:
the answer is the a affects the width
Step-by-step explanation:
the answer is a not the choice A, the third one
(i hope this help)
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
The answer is A = P²/16
The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²
Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.
Step 1:
P = 4s
s = P/4
Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
Answer:
multiply each by -1
-5/6 x -1 = 5/6
-7 3/8 x -1 = 7 3/8
-3/11 x -1 = 3/11
Step-by-step explanation:
The formula for the lateral surface area of a right circular cone is:
where r is the radius of the base, and l is the slant height.
Plugging in the values we get:
