Answer:
i can
Step-by-step explanation:
The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.
<h3>How to calculate probability?</h3>
The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:
= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]
= 42/220 + 18/66
= 0.1909 + 0.2727
= 0.4179
In conclusion, the probability is 0.4179.
Learn more about probability on:
brainly.com/question/24756209
Answer:
420.9
Step-by-step explanation:
420.86827 ≈ 420.9 because we need to round to one decimal place.
Since 6 is greater than 5, we round 8 up to make it 9
420.9
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-Chetan K
We first calculate the z-score corresponding to x = 1075 kWh. Given the mean of 1050 kWh, SD of 218 kWh, and sample size of n = 50, the formula for z is:
z = (x - mean) / (SD/sqrt(n)) = (1075 - 1050) / (218/sqrt(50)) = 0.81
From a z-table, the probability that z > 0.81 is 0.2090. Therefore, the probability that the mean of the 50 households is > 1075 kWh is 0.2090.
