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Alexxx [7]
3 years ago
10

Answer if u know both plzz help

Mathematics
1 answer:
NARA [144]3 years ago
4 0
4) Answer is D.
Irrational numbers cannot be classified as rational numbers

5) Answer is B.
Every irrational number is a real number
You might be interested in
Find angle E if angle E and angle F are supplementary, angle E= 2x + 15 and angle F= 5x - 38
miss Akunina [59]

Answer:

Angle E = 73 degrees

Step-by-step explanation:

Supplementary means it equals 180 degrees.

So to find x, you add the 2 equations.

2x + 15 + 5x - 38 = 180

which equals 7x + (-23) = 180 = 7x - 23 = 180

7x = 203  You move the -23 to the other side

203/7 = 29  So x = 29 degrees

So to find angle E, you put in 29 degrees for x.

2 x 29 + 15 = 73 degrees

7 0
3 years ago
Find the point(s) of intersection for<br> y = x2 + 3x – 4 and y = 4x + 2
Greeley [361]

Answer:

(6,26)

Step-by-step explanation:

You will take the points and graph them since these are both positive equations they will go up and to the right.

both intersect at (6,26)

also if you forgot how to graph it, I got you

1. find the rate of change (as I will call it) THIS IS YOUR NUMBER NEXT TO THE X!!! this means that the line will go up 4 and over 1 then your whole number, in this example would be 2 is your y-intersect (the place on the y-axis where the line passes) after that you should be able to draw your lines and find the poi!

Please comment if I got something wrong! I don't want to be giving bad advice

6 0
3 years ago
Find the distance between the points (5, -6) and (-1, 3).
emmasim [6.3K]

Answer:

\sqrt{117}

Step-by-step explanation:

Use the distance formula.

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

d = \sqrt{(-1 - 5)^2 + (3 - (-6))^2}

d = \sqrt{(-6)^2 + 9^2}

d = \sqrt{36 + 81}

d = \sqrt{117}

6 0
3 years ago
Need help asap<br> brainly guaranteed
Bas_tet [7]
I believe the answer is H
4 0
3 years ago
Read 2 more answers
Evaluate the piecewise-defined function for the indicated values. I’m just unsure of how to solve when the value isn’t given dir
Fantom [35]

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for m^{2} +1 is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and \sqrt{t-1} for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at m^{2} +1 when m belongs to \sqrt{7} and \sqrt{10} the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

Learn more about functions at brainly.com/question/10439235

#SPJ10

6 0
2 years ago
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