Answer:
90% CI expects to capture u 90% of time
(a) This means 0.9 * 1000 = 900 intervals will capture u
(b) Here we treat CI as binomial random variable, having probability 0.9 for success
n = 1000
p = 0.9
For this case, applying normal approximation to binomial, we get:
mean = n*p= 900
variance = n*p*(1-p) = 90
std dev = 9.4868
We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)
We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s
so z1 = (889.5 - 900 )/9.4868 = -1.11
so z2 = (910.5 - 900 )/9.4868 = 1.11
P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)
= 0.8665 - 0.1335
= 0.733
1 and they split the other in half
Answer:
i need help on my test
Step-by-step explanation:
Answer:
Step-by-step explanation:
The Law of Cosines gives an immediate result. No translation to Cartesian coordinates is necessary. That law makes use of the angle between the vectors, u2-u1
Answer:
Number of adults that attended the show = 400
Number of children that attended the show = 359
Total people who attended the show = 759
Step-by-step explanation:
Total earned = 15,385
Adults = $25
Children = $15
Let
Adults = A
Children = C
The number of adults who attendee the show was 41 more than the number of children who attended the show
A = C + 41
25A + 15C = 15,385
Substitute
A = C + 41
25(C+41) + 15C = 15,385
25C + 1,025 + 15C = 15,385
40C + 1,025 = 15,385
40C = 15,385 - 1,025
40C = 14,360
Divide both sides by 40
C = 14,360 / 40
= 359
C = 359
Substitute C = 359 into
A = C + 41
A = 359 + 41
= 400
A = 400
Number of adults that attended the show = 400
Number of children that attended the show = 359
Total people who attended the show = 759
