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kolbaska11 [484]
4 years ago
14

A medium-sized jet has a 3.8-m-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to the

cylindrical fuselage, and aerodynamic shaping gives it a drag coefficient of 0.37. How much thrust must the jet’s engines provide to cruise at 230 m/s at an altitude where the air density is 1.0 kg/m3?

Engineering
1 answer:
Monica [59]4 years ago
7 0

Answer:

Fthrust = 110.99 kN

Explanation:

Model:

Ignore the drag on the wings and focus on the cylindrical fuselage.

Visualize:

The net force is zero as the jet cruises at 230 m/s, so the thrust must be equal in magnitude to the drag. The  gravitational and lift forces are equal in magnitude and opposite in direction.

Given

D = 3.80 m  ⇒ R = D / 2 = 3.80 m/ 2 = 1.90 m

C = 0.37

ρ = 1.0 kg/m³

v = 230 m/s

m = 85,000 kg

Fthrust = ?

We show the Free Body Diagram in the pic.

Then, we apply

∑Fx = 0  (→+)

Fthrust = Fdrag = (1/2)*C*ρ*A*v²

A = π*R² = π*(1.90 m)² = 11.34 m²

⇒  Fthrust = (1/2)*(0.37)*(1.0 kg/m³)*(11.34 m²)*(230 m/s)²

⇒  Fthrust = 110990.159 N = 110.99 kN

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A three-story school has interior column bays that are spaced 25 ft apart in both directions. If the loading on the flat roof is
Lady_Fox [76]

Answer:

Explanation:

Floor Load:

Lo= 50psf

At= 25x25 = 625 square feet

L= Lo(0.25 +15/\sqrt{KuAt)}

L=50(0.25+15/\sqrt{(4)(625)}= 13.1psf

%reduction= 13.1/50 = 26%

Fr= 3[(13.1psf)(25ft)(25ft)+(20psf)(25ft)(25ft)]= 62k

7 0
3 years ago
Poles are values of Laplace transform variable, s, that make denominator of transfer function zero. Zeros are values of Laplace
Ostrovityanka [42]

Answer:

Zero 1 = -1

Zero 2 = -3

Pole 1 = 0

Pole 2 = -2

Pole 3 = -4

Pole 4 = -6

Gain = 4

Explanation:

For any given transfer function, the general form is given as

T.F = k [N(s)] ÷ [D(s)]

where k = gain of the transfer function

N(s) is the numerator polynomial of the transfer function whose roots are the zeros of the transfer function.

D(s) is the denominator polynomial of the transfer function whose roots are the poles of the transfer function.

k [N(s)] = 4s² + 16s + 12 = 4[s² + 4s + 3]

it is evident that

Gain = k = 4

N(s) = (s² + 4s + 3) = (s² + s + 3s + 3)

= s(s + 1) + 3 (s + 1) = (s + 1)(s + 3)

The zeros are -1 and -3

D(s) = s⁴ + 12s³ + 44s² + 48s

= s(s³ + 12s² + 44s + 48)

= s(s + 2)(s + 4)(s + 6)

The roots are then, 0, -2, -4 and -6.

Hope this Helps!!!

3 0
4 years ago
Lithium at 20°C is BCC and has a lattice constant of 0.35092 nm. Calculate a value for the atomic radius of a lithium atom in na
Nutka1998 [239]

Answer:

the atomic radius of a lithium atom is 0.152 nm

Explanation:

Given data in question

structure = BCC

lattice constant  (a) = 0.35092 nm

to find out

atomic radius of a lithium atom

solution

we know structure is BCC

for BCC radius formula is \sqrt{3} /4 × a

here we have known a value so we put a in radius formula

radius =  \sqrt{3} /4 × a

radius =  \sqrt{3} /4 × 0.35092

radius = 0.152 nm

so the atomic radius of a lithium atom is 0.152 nm

5 0
3 years ago
With thermodynamics, one cannot determine ________.
zloy xaker [14]

Answer:

Option B is correct.

Explanation:

With thermodynamics, one cannot determine the speed of the reaction.

Speed of the reaction is defined as the rate at which one component is changes to another component. With factor cannot be calculated from the thermodynamics branch of engineering.

With thermodynamics we can determine the value of the equilibrium constant,

the extent of a reaction, the temperature at which a reaction will be spontaneous & the direction of a spontaneous reaction. But we cannot determine  the speed of a reaction.

Therefore option B is correct.

4 0
3 years ago
Estimate horizontal and vertical tail sizes fo r a twin-turboprop regional transport with wing area of 40 m2, aspect ratio of 10
svetlana [45]

Answer: 0.2m sqr

Explanation:

A well behaved aircraft basically have a value of volume in horizontal and vertical area.

Volume in horizontal area (Vh) = 0.6

Volume in vertical area (Vv) = 0.05

Having known this, consider the relationship to find the vertical and horizontal tail sizes.

Vertical tail area (Sv)

Horizontal tail area (Sh)

Vh= (Sh × I) / S

Where,

I = moment

S= wing area

Sh= Horizontal tail area

Vh= Volume in horizontal area

0.6= Sh × 10/40

24= 10Sh

Sh= 24/10

Sh= 2.4 msqr

Horizontal tail area= 2.4m sqr

From the information above, we can calculate the vertical tail area.

Vertical tail area is calculated thus below:

Vv= (Sv× I) / S

Where

Vv= Volume in vertical area

Sv= Vertical tail area

I= Moment

S= Wing area

Therefore

Sv= (Vv × S) /I

Sv= (0.05×40)/10

Sv= 0.2msqr

In conclusion, the vertical tail size is 0.2msqr

7 0
3 years ago
Read 2 more answers
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