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kodGreya [7K]
3 years ago
8

What design advantages can you identify in the location of the controller

Engineering
1 answer:
lubasha [3.4K]3 years ago
8 0

Find case studies · Learn about meeting solutions · Review analyst reports ... Design FAQ ... Q. How do I configure the switch to connect with the WLC? ... This is precisely one of the greatest advantages of having WLCs in your wireless network. ... out the ARP request to the client will not know where the client is located.

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A satellite at a distance of 36,000 km from an earth station radiates a power of 10 W from an
notsponge [240]
This an example solved please follow up with they photo I sent ok

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3 years ago
ممكن الحل ............
Roman55 [17]

Answer:

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Explanation:

4 0
4 years ago
You set a sensor to transmit the wind speed on top of a mountain. Which of these languages are you most likely to have used?
kifflom [539]

The programming language that is most likely used to transmit the wind speed is: B. SQL.

<h3>What is SQL?</h3>

SQL is an acronym for structured query language and it can be defined as a domain-specific programming language that is designed and developed for the management of various data that are saved in a relational or structured database.

This ultimately implies that, a structured query language (SQL) can be used to communicate with a database in accordance with the American National Standards Institute (ANSI) standards.

In conclusion, the programming language that is most likely used to transmit the wind speed is SQL.

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brainly.com/question/25266787

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8 0
2 years ago
A highway reconstruction project is being undertaken to reduce crash rates. The reconstruction involves a major realignment of t
CaHeK987 [17]

Answer:

The provided length of the vertical curve is satisfactory for the reconstruction design speed of 60 mi/h

Explanation:

The explanation is shown on the first uploaded image

8 0
3 years ago
Consider a Carnot heat pump cycle executed in a steady-flow system in the saturated mixture region using R-134a flowing at a rat
attashe74 [19]

Answer:

7.15

Explanation:

Firstly, the COP of such heat pump must be measured that is,

              COP_{HP}=\frac{T_H}{T_H-T_L}

Therefore, the temperature relationship, T_H=1.15\;T_L

Then, we should apply the values in the COP.

                           =\frac{1.15\;T_L}{1.15-1}

                           =7.67

The number of heat rejected by the heat pump must then be calculated.

                   Q_H=COP_{HP}\times W_{nst}

                          =7.67\times5=38.35

We must then calculate the refrigerant mass flow rate.

                   m=0.264\;kg/s

                   q_H=\frac{Q_H}{m}

                         =\frac{38.35}{0.264}=145.27

The h_g value is 145.27 and therefore the hot reservoir temperature is 64° C.

The pressure at 64 ° C is thus 1849.36 kPa by interpolation.

And, the lowest reservoir temperature must be calculated.

                   T_L=\frac{T_H}{1.15}

                        =\frac{64+273}{1.15}=293.04

                        =19.89\°C

the lowest reservoir temperature = 258.703  kpa                    

So, the pressure ratio should be = 7.15

8 0
3 years ago
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