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antiseptic1488 [7]
3 years ago
6

If 20 kg of iron, initially at 12 °C, is added to 30 kg of water, initially at 90 °C, what would be the final temperature of the

combined system? (Hint: the heat given up by the water will be equal to the heat gained by the iron) Explain how you would represent this problem in the simulation.
Engineering
1 answer:
rjkz [21]3 years ago
5 0

Answer:

final temperature of the combined system T = 84.78°C

Explanation:

Given data

mass of iron ( m1 )   = 20 kg

temperature iron ( t1 ) =  12 °C

mass of water ( m2 ) = 30 kg

temperature of water ( t2 )   =  90 °C

To find out

final temperature of the combined system

solution

we know the energy requirement formula to rise the temp

energy = mass × specific heat  × change in temperature  

we combine both system so both energy will be added

and

we know specific heat of iron ( c1 ) = 0.450 kJ/kg

and specific heat of water ( c2 ) = 4.186 kJ/kg

4.186 joule/gram °C

now combine both energy

energy = mass, m1 × specific heat, c1  × change in temperature, T - t1 + mass, 2 × specific heat, c2  × change in temperature, T - t2

energy = 20 × 0.450  × T - 12  + 30 × 4.186 × T -90

(20)(0.45)(T−12)=(30)(4.186)(90−T)

final temperature of the combined system T = 84.78°C

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3 years ago
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Fatigue occurs under conditions of high elastic stress, high stress fluctuations and high rate of loading

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Answer:

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= 204.1 Ohm

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Xc = 1/2πfC

Xc = 1/2×3.14×50×4.80μF

= 1/0.0015072

= 663.48Ohms

1. Total impedance, Z = sqrt (R^2 + (Xc-XL)^2)= √ 301^2+ (663.48Ohms - 204.1 Ohm)^2

√ 90601 + (459.38)^2

√ 90601+211029.98

√ 301630.9844

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