Answer:
0.289
Explanation:
Since the body is in equilibrium ( no net movement), then the total upward force must equal the total downward force and also total forward force must equal total backward force
Tension in the rope inclined at 30⁰ to the vertical hhas vertical and horizontal components
vertical component = Tcos 30⁰ and horizontal component = T sin30⁰
T cos 30⁰ = the downward force = mg where m is the mass of 5kg and g is 9.8 m/s² acceleration due to gravity
T cos 30⁰ = 49
T in the inclined rope to the vertical = 49 / cos 30⁰ = 56.58 N
Horizontal component of the tension in the rope = T sin30⁰ = 56.58 sin 30⁰ = 28.29 N
since the 10kg was not moving the frictional force impeding the movement = the horizontal component of the T along the positive x axis since the frictional force will act along the negative x axis
Fr = 28.29 N
coefficient of static friction = Fr / normal (mg) = 28.29 / (10 × 9.8) = 0.289
