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matrenka [14]
3 years ago
13

You are traveling through the forest and encounter an ancient well. You want to know how deep the well is. If you drop a coin an

d hear it hit the bottom of the well in 3 seconds, how deep is the well?
Physics
2 answers:
eimsori [14]3 years ago
4 0

Answer:

About 30 ft

Explanation:

horrorfan [7]3 years ago
3 0
Depth = 1/2 x 9,8 x 9 = 44.1 m
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A bus accelerates to 60 m/s to the east in 10 s. What is the buses acceleration? 2. A car traveling at 10.0 m/s to the west acce
professor190 [17]

Answers:

1) a=6\frac{m}{s^{2}}

2) t=8s

Explanation:

1) Acceleration a is defined as the variation of Velocity V in time t :  

a=\frac{V}{t}  (1)

A body also has acceleration when it changes its direction.

In this case we have a bus with a velocity of 60m/s to the east, that accelerates in a time 10s. So, we have to find the bus's acceleration:

a=\frac{60m/s}{10s}  (2)

a=6m/s^{2}  (3)  This is the bus's accelerration

2) Now we have a car that accelerates 2m/s^{2}  to the west in order to reach a speed of 16m/s in the same direction, and we have to find the time t it takes to the car to reach that velocity.

Therefore we have to find  t from (1):

t=\frac{V}{a}  (4)

t=\frac{16m/s}{2m/s^{2}}  (5)

Finally:

t=8s  (6)

3 0
3 years ago
What is the order of magnitude of the distance of Sun to nearest star in meters?
neonofarm [45]

Answer:

Approximating the Milky Way as a disk and using the density in the solar neighborhood, there are about 100 billion stars in the Milky Way.

Explanation:

Since we are making an order of magnitude estimate, we will make a series of simplifying assumptions to get an answer that is roughly right.

Let's model the Milky Way galaxy as a disk.

The volume of a disk is:

V

=

π

⋅

r

2

⋅

h

Plugging in our numbers (and assuming that

π

≈

3

)

V

=

π

⋅

(

10

21

m

)

2

⋅

(

10

19

m

)

V

=

3

×

10

61

m

3

Is the approximate volume of the Milky Way.

Now, all we need to do is find how many stars per cubic meter (

ρ

) are in the Milky Way and we can find the total number of stars.

Let's look at the neighborhood around the Sun. We know that in a sphere with a radius of

4

×

10

16

m there is exactly one star (the Sun), after that you hit other stars. We can use that to estimate a rough density for the Milky Way.

ρ

=

n

V

Using the volume of a sphere

V

=

4

3

π

r

3

ρ

=

1

4

3

π

(

4

×

10

16

m

)

3

ρ

=

1

256

10

−

48

stars /

m

3

Going back to the density equation:

ρ

=

n

V

n

=

ρ

V

Plugging in the density of the solar neighborhood and the volume of the Milky Way:

n

=

(

1

256

10

−

48

m

−

3

)

⋅

(

3

×

10

61

m

3

)

n

=

3

256

10

13

n

=

1

×

10

11

stars (or 100 billion stars)

Is this reasonable? Other estimates say that there are are 100-400 billion stars in the Milky Way. This is exactly what we found.

4 0
2 years ago
Read 2 more answers
What is an electric circuit?
klemol [59]

<h3>Answer: any path that allows electrons to flow</h3>

An electrical circuit is a path in which electrons from a voltage or current source flow. ... The part of an electrical circuit that is between the electrons' starting point and the point where they return to the source is called an electrical circuit's "load".

7 0
3 years ago
Read 2 more answers
In the physics of motion a force acting over a distance is?​
lutik1710 [3]
A force over distance is work the unite is joules
8 0
4 years ago
Read 2 more answers
A pitcher is in 85° of abduction, holding a 1.4 N baseball at point C, 65 cm from the joint axis at point O • The center of grav
erastovalidia [21]

I attached a Diagram for this problem.

We star considering the system is in equlibrium, so

Fm makes 90-(\theta+5) with vertical

Fm makes 70 with vertical

Applying summatory in X we have,

\sum F_x = 0

W+1.4-Fm cos(70)

We know that W is equal to

W= 0.06*100N = 6N

Substituting,

Fm cos (70) = W+1.4N

Fm cos (70) = 6N + 1.4N

Fm = \frac{7.4}{cos(70)}

Fm = 21.636N

<em>For the second part we know that the reaction force Fj on deltoid Muscle is equal to Fm, We can assume also that</em> \beta  = \theta

3 0
3 years ago
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