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3 years ago

50 POINTS, WILL GIVEE BRAINLIEST

Mathematics

2 answers:

Leni [432]3 years ago

8 0

Answer:

irational

Step-by-step explanation:

rational.

vichka [17]3 years ago

6 0

Answer:

The order goes as follows: rational, non rational, rational.

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Given the figure below, find the values of x and z

viktelen [127]

Answer:

x=6 the angle =88

z=92

Step-by-step explanation:

find x

92+11x+22=180

114+11x=180

11x=180-114

x=66/11

x=6 the angle is 11(6)+22=66+22=88

find z=

z+88=180

z=180-88=92

8 0

3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

NEED HELP ASAP!!!!!!!!!!!!

Mice21 [21]

Answer:

p(0) = 800

p(8) = 997

Step-by-step explanation:

p(t) = 800 * (1.028)^t

The current price is when t=0

p(0) = 800 * (1.028)^0

= 800(1)

= 800

The price in 8 years

p(8) = 800 * (1.028)^8

=997.7802522414861936754688

To the nearest dollar

= 998

8 0

3 years ago

Read 2 more answers

Fiona found 47 pens for $3.00 . Please help Fiona by figuring out the ratio. (round to 2 decimal places)

shepuryov [24]

Answer:

0.06

Step-by-step explanation:

3/47

4 0

2 years ago

Find all solutions for the following equations. Write your answers in radians using exact values. (Enter your answers as a comma

sasho [114]

Answer:

Step-by-step explanation:

Given that:

sin2xcos x + cos2xsin x = -1

Recall that;

SInAcosB + cosASinB = SIn (A+B)

SIn (2x +x) = -1

Sin (3x) = -1

$x = \bigg [\dfrac{Sin ^{-1} (-1)}{3} \bigg ]$

$x = \dfrac{\pi}{2} + \dfrac{2 \pi \ k}{3}$

$x = \dfrac{\pi}{2}, \dfrac{7 \pi}{6}, \dfrac{11 \pi}{6}$

5 0

3 years ago