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Andreyy89
3 years ago
10

The force of repulsion between two identical positive charges is 0.800 N when the charges are 0.100 m apart. Find the value of e

ach charge.
Physics
1 answer:
puteri [66]3 years ago
8 0

Answer:

Value of each charge is given as

q = 9.43 \times 10^{-7} C

Explanation:

As we know that electrostatic force between two charges is given as

F = \frac{kq_1 q_2}{r^2}

here we know that

q_1 = q_2 = q

F = 0.800 N

r = 0.100 m

now we have

F = \frac{(9\times 10^9) q^2}{(0.100)^2}

0.800 = 9\times 10^{11} q^2

q = 9.43 \times 10^{-7} C

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