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3 years ago

This is a measure of mass per unit volume.

Physics

1 answer:

Rudik [331]3 years ago

8 0

the answer would be density, because density is exactly that: a measure of mass per unit of volume.

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What effect does pollution have on plant growth?

Dafna11 [192]

All around the world, different pollutants enter the environment causing pollution towards our planet growth. Nature can easily be polluted killing plants, food resources, and even effecting our water. This will cause the environment's acidity to lower majorly. Changing the planets normal growth.

Hope I could help! :)

4 0

4 years ago

Un acróbata de 60.0 kg está unido a un cordón de bungee con un resorte de 10.0 m de longitud . Salta de un puente que abarca un

Ede4ka [16]

Answer:

What kind of languege is this please?

8 0

2 years ago

A monatomic ideal gas in equilibrium at a pressure of 3 kPa and a temperature of 300 K is initially confined in a volume of 1.3

GuDViN [60]

To solve this problem, it is necessary to apply the concepts related to the change of entropy in function of the Volume in two states due to the number of moles and the ideal gas constant, this can be expressed as

$\Delta S = nRln(\frac{V_2}{V_1})$

Where,

R = Gas constant

V = Volume (at each state)

At the same time the number of moles of gas would be determined by the ideal gas equation, that is,

$n = \frac{PV}{RT}$

Where,

P = Pressure

V = Volume

R = Gas Constant

T = Temperature

$n = \frac{(1000Pa)(1.3m^3)}{(300K)(8.314Pa\cdot m^3\cdot K^{-1}\cdot mol^{-1})}$

$n = 0.521mol$

Using the value of moles to replace it in the first equation we have

$\Delta S = (0.521mol)(8.314Pa\cdot m^3\cdot K^{-1}\cdot mol^{-1})ln(\frac{10.3m^3}{1.3m^3})$

$\Delta S = 9.01J/K$

Therefore the correct option is A.

7 0

4 years ago

What is air resistance means explain it with free falling body

NikAS [45]

In freely falling body, there is no force acting on it other than the force of gravity (g).

8 0

3 years ago

The elementary particle called a muon is unstable and decays in about 2.20μs2.20μs , as observed in its rest frame, into an elec

vredina [299]

Answer:

5.865 μs

Explanation:

t₀ = Time taken to decay a muon = 2.20 μs

c = Speed of Light in vacuum = 3×10⁸ m/s

v = Velocity of muon = 0.927 c

t = Lifetime observed

Time dilation

$t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-\frac{(0.927c)^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-0.927^2}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{0.140671}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{0.3750}\\\Rightarrow t=5.865\times 10^{-6}\ seconds$

∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs

3 0

3 years ago