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uysha [10]
3 years ago
9

le=" | \frac{4}{3} (x + 3) | = 8" alt=" | \frac{4}{3} (x + 3) | = 8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Serggg [28]3 years ago
4 0
Sheeesh that’s a hard one
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(4a - 3b + 4c) + (8a - 2b + 3c)
Monica [59]

Answer:

<em>Hey mate, here's ur answer:</em>

<em>----------------------------------------------------------</em>

<em>(4a - 3b + 4c) + (8a - 2b + 3c)</em>

=4a+−3b+4c+8a+−2b+3c

=(4a+8a)+(−3b+−2b)+(4c+3c)

<u>=12a−5b+7c</u>

----------------------------------------------------------

<em>Hope it helps</em>

<em>#stayhomestaysafemate</em>

<em>:D</em>

5 0
3 years ago
I need help on with to find<br> 24 1/2-4 3/5
schepotkina [342]

Answer:

24.50 - 4.6 =  19.9

Step-by-step explanation:

24 1/2-4 3/5

24.50 - 4.6 =  19.9

6 0
3 years ago
Read 2 more answers
The equation of the line through point (- 4, 0) and parallel to the y-axis is
riadik2000 [5.3K]
The gradient of y axis is zero. Since the line is parallel to y axis, its gradient is also zero. This
y=mx+c
Where m is the gradient;
y=(0)x+c
y=c
Replacing for y and x;
0=0(-4)+c
c=0
7 0
3 years ago
Evaluate 8-m/n+p^2 when m=8 and n=2 and p=7
Lynna [10]

Answer:

-45

Step-by-step explanation:

8 - 8 / 2 + 7^2

PEMDAS Parenthesis Exponents Multiplication Division Addition Subtraction

Exponents 7^2 = 49

8 - 8 / 2 + 49

Division 8 / 2 = 4

8 - 4 + 49

Addition 4 + 49 = 53

8 - 53

Subtraction 8 - 53 = -45

-45

6 0
4 years ago
Find how many solutions there are to the given equation that satisfy the given condition. X1 + x2 + x3 = 22, each x; is a positi
DiKsa [7]

Answer:

Step-by-step explanation:

Given that there are three variables satisfying the equation

X1 + x2 + x3 = 22

Here each x is given to be a positive integer

i.e. solution set for each of the variable can be any integer from 1 to 20 at most.(because if two other integers are 1 each third has to be 20)

Hence solution set can be of the form

(x1,x2,x3) =(1,1,22) (1,2,21) (1,3,20).....

=(2,1,19) (2,2,18),...\\=(3,1,18) (3,2,17),....\\...\\...\\=(20,1,1)

If x1 =1, there are 20 solution sets

If x1 =2,there are 19

...

If x1 =20 there is 1 set

Hence total solutions can be= 20+19+...+1\\=\frac{20(21)}{2} =210

6 0
3 years ago
Read 2 more answers
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