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Maksim231197 [3]
3 years ago
15

Use inductive reasoning to write the five square numbers that follow 25

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0
If we observe the square numbers series, we can understand a pattern:
 1,4,9,16,25.
 In other words, we have the following
 1+3=4
 4+5=9
 9+7=16
 16+9=25
 In this pattern, we added 3,5,7 and 9 respectively to the previous number. In this way, to get the next numbers, we need to add 11,13,15,17 and 19 respectively to get the answer to previous number.
 25+11=36
 36+13=49
 49+15=64
 64+17=81
 81+19=100
 So, the five square numbers that follow 25 are 36, 49, 64, 81, 100.
 answer
 36, 49, 64, 81, 100.

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dedylja [7]
3^2(6-2)*(4-6)/3
=(9*4)*(-2/3)
=36*(-2)/3
= -72/3
= -24 (answer)
4 0
3 years ago
Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
SUPER EASY FOR POINTS!!!!solve: x-3=3x-2
Savatey [412]

Answer:

Polynomial equation solver

x-3=3x-2

Standard form:

−2x − 1 = 0

Factorization:

−(2x + 1) = 0

Solutions:

x = −1

2

= -0.5

3 0
3 years ago
Which three lengths could be the lengths of the sides of a triangle? Thanks
Nataly_w [17]

s1+s2>s3  where s1 and s2 are the 2 smaller sides

Choice C is the only 1 that fits

7+13 >18

7 0
3 years ago
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