Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
We know that
[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube
The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=<span>5 cm
T</span>he biggest block was 729 cm³------> b3=√729------> b3=<span>9 cm
[</span><span>the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm
</span><span>
the answer is
</span>the stack of blocks was 18 cm tall<span>
</span>
Answer:
2
Step-by-step explanation:
The common ratio of the sequence is 2 because between each term you are multiplying by 2 to get the next term
