Answer:
Explanation:
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In this case, since the density in the international system of units is given in terms of kg for the mass and L for the volume, we need to perform a process of units conversions from mg and dL to kg and L as show below:
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<u>Answer:</u> The theoretical yield and percent yield of is 3.93 g and 30.53 % respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of = 4.00 g
Molar mass of = 238 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of to form
follows:
By Stoichiometry of the reaction:
1 mole of produces 1 mole of
So, 0.0168 moles of will produce =
of
Now, calculating the mass of from equation 1, we get:
Molar mass of = 234 g/mol
Moles of = 0.0168 moles
Putting values in equation 1, we get:
To calculate the percentage yield of , we use the equation:
Experimental yield of = 1.20 g
Theoretical yield of = 3.93 g
Putting values in above equation, we get:
Hence, the theoretical yield and percent yield of is 3.93 g and 30.53 % respectively
Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:
The amount of salt needed for the calculated amount of seawater is: