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Alona [7]
2 years ago
5

Exactly 1.5 g of a fuel burns under conditions of constant pressure and then, in a

Chemistry
1 answer:
Gwar [14]2 years ago
7 0

Answer:

At a constant pressure the production of heat will be 25.9 KJ.

Explanation:

The heat produces at constant pressure will be more as compared to the heat produced at constant volume because,

At a constant pressure there is some work done and heat is used in this process. All the heat is not going to change the temperature. while,

At constant volume there is no work done and all the heat is going to change the temperature. In other words we can say that it take less heat to produce the temperature change at  a constant volume as compared to at constant pressure.

Cv ∠ Cp

So, when 1.5 g of fuel is burn at constant pressure it will produce 25.9 KJ. while at constant volume it will produce 23.3 KJ.

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Consider the following first-order reaction: A → B. The concentration of A at the start of the reaction is 4.17 M and after 4.84
valina [46]

Answer : The value of rate constant is, 0.0327s^{-1}

Explanation :

First we have to calculate the rate constant, we use the formula :

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 4.84 s

a = initial concentration = 4.17 M

a - x = concentration after time 4.84 s = 3.56 M

Now put all the given values in above equation, we get

k=\frac{2.303}{4.84}\log\frac{4.17}{3.56}

k=0.0327s^{-1}

Therefore, the value of rate constant is, 0.0327s^{-1}

4 0
2 years ago
Vanadium has an atomic mass of 50.9415 amu. It has two common isotopes. One isotope has a mass of 50.9440 amu and a relative abu
grandymaker [24]

Answer:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

Explanation:

6 0
3 years ago
An animal which eats plants and animals is a(n)
Vilka [71]

Answer:

An Omnivore

Explanation: An <u>omnivore</u> is a kind of animal that eats either other animals or plants. Some omnivores will hunt and eat their food, like carnivores, eating herbivores and other omnivores. Some others are scavengers and will eat dead matter. Many will eat eggs from other animals.

Omnivores eat plants, but not all kinds of plants. Unlike herbivores, omnivores can't digest some of the substances in grains or other plants that do not produce fruit. They can eat fruits and vegetables, though. Some of the insect omnivores in this simulation are pollinators, which are very important to the life cycle of some kinds of plants.

6 0
3 years ago
4Al(s) + 30₂(g) → 2Al2O3 (s)
Margaret [11]
1) 1 molecules
2) 2 oxygen atoms
3)2 moles of Al2O3 are formed
4)4:3
6 0
2 years ago
What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C
Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = \frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\

Now use the molar ratio to find how many moles of NaOH would be required to neutralize 5.5537*10^{-3} mol\\ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

         1           :            2                  (we get this from the balanced equation)

5.5537*10^{-3} mol\\ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L

5 0
3 years ago
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