Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively
Explanation:
Moles of cyclohexane = 0.069 mole
Volume of solution = 2.8 L
Initial concentration of cyclohexane =![\frac{moles}{Volume}=\frac{0.069}{2.8}=0.025M](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7BVolume%7D%3D%5Cfrac%7B0.069%7D%7B2.8%7D%3D0.025M)
The given balanced equilibrium reaction is,
cyclohexane ⇔ methylcyclopentane
Initial conc. 0.025 M 0
At eqm. conc. (0.025-x)M (x) M
The expression for equilibrium constant for this reaction will be,
K= methylcyclopentane / cyclohexane
Now put all the given values in this expression, we get :
![0.12=\frac{(x)}{(0.025-x)}](https://tex.z-dn.net/?f=0.12%3D%5Cfrac%7B%28x%29%7D%7B%280.025-x%29%7D)
By solving the term 'x', we get :
x = 0.0027
Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M
Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M