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storchak [24]
2 years ago
11

What is the formula for nickel(III) carbide?

Chemistry
2 answers:
mylen [45]2 years ago
7 0

Answer:

Ni3C

Explanation:

andrew11 [14]2 years ago
5 0
I think the answer is Ni3C
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Based on the hierarchical organization, order these terms from smallest to largest.
erik [133]
From smallest to largest it will be first Carbon,Water,Carbohydrate,Mitochondria, Skin Cell.
4 0
3 years ago
Read 2 more answers
s sample of thorium-234 has a half life of 25 days. will all the thorium undergo radioactive decay in 50 days?
Assoli18 [71]

Answer:

25% thorium will left after 50 days.

Explanation:

Half life:

A nuclear half is the time period of radioactive material in which its amount remain halved.

In given question it is stated that the half life thorium-234 is 25 days. Which means after passing the 25 days the amount of thorium must be halved of original amount.

For example,

If the original concentration was 100%, than after 25 days it will be 50%.

After 50 days amount of thorium left:

Number of half life = T (elapsed) / T half life

Number of half life = 50/25

Number of half life =  2

At first half life amount of thorium left = 100/2 = 50

After second half life amount of thorium left = 50/2 = 25

Total amount decayed = 50+25 = 75

Amount left after 50 days = 100-75 = 25

25% thorium will left after 50 days.

5 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
3 years ago
4. Why can't the subscripts be changed in a chemical equation in chemistry
neonofarm [45]
If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
4 0
3 years ago
Somebody answer please a picture is attached!??
DanielleElmas [232]
9.2 that is the answer
7 0
3 years ago
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