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fenix001 [56]
3 years ago
14

Which metal is most likely to form more than one kind of positively charged ion

Chemistry
2 answers:
Aleks [24]3 years ago
6 0

Answer:

Nickel (Ni) is most likely to form more than one kind of positively charged ion as it is a transition metal and all of the ther metals have a fixed ion charge.

Na becomes Na+

Ba becomes Ba +2

Mg becomes Mg+2

Explanation:

please mark brailiest

polet [3.4K]3 years ago
6 0

Answer:

metal atoms lose electrons to form positivity charged ions. non metal atoms gain electrons to form negatively charged ions

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1. Plants that perform photosynthesis convert sun (solar) energy to<br> food energy.
Alinara [238K]

Answer:

true

Explanation:

one reason is because plants need sunlight and water because it is their source of food

3 0
3 years ago
How many grams are 3.01 × 1023 molecules of CuSO4?
zvonat [6]
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
4 0
3 years ago
2)
Darya [45]
The answer is B. Continental Drift (Confidently)
7 0
3 years ago
Wild animals are not considered a natural resource.
Anvisha [2.4K]

Answer:

False

Explanation:

Wild animals are found in an ecosystem and they are considered to be a natural resource and a biotic factor in the environment. They are living things so they are a natural resource.

4 0
3 years ago
In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con
klemol [59]

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by =K_p=0.150

Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)

initial

0       0         0.500 atm

At equilbrium

p      p       (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

 K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}

0.150=\frac{(0.500-2p)^2}{p\times p}

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

7 0
3 years ago
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