When a non volatile solute is added to a solvent, the vapor pressure of the solvent will decrease.
Vapor pressure is a colligative property. Which means that it will be affected by the number of particles of solute.
The relationship between the concentration of the solute and the vapor pressure is given by Roult's Law
ΔP = Xsolute * P, where ΔP is vapor pressure lowering, Xsolute is the molar fractionof the solute, and P is the vapor pressure of the solvent.
Then lets find Xsolute
X solute = # moles solute / # moles solution
# moles solute = 75.0 grams / molar mass
molar mass of C12H22O11 = 12*12g/mol + 22*1g/mol + 11*16g/mol = 342 g/mol
# moles solute = 75.0/342 mol = 0.219 mol
# moles of solvent = grams of solvent / molar mass of solvent
# moles of solvent = 180 grams /18 g/mol = 10 mols
Xsolute = 0.219 mol solute / (10 + 0.219) mol solution =0.0215
ΔP = 0.0215*26.7 torr = 0.57 torr
Answer= 0.57 torr
Answer:
The net force is 5 N and to the left.
Explanation:
37 N - 32 N = 5 N and since there is a stronger pull from the rope moves towards the left so the direction of motion is left.
The chemist envision reaction take place when molecules/atoms collide with respect to the correct amount of energy and in the correct position so that the bond can be formed.These means that the reaction take place when two or more molecules collides and a reaction occurs.
Answer:
2.07 mol O₂
Explanation:
First we need to write down the species present in the chemical equation, using the information given by the exercise:
However this equation <em>is not balanced</em>, so now we<u> balance it</u>:
Now we can use the stoichiometric ratio to <u>calculate the moles of oxygen </u>from the moles of sulfide dioxide:
- 1.38 molSO₂ *
= 2.07 mol O₂
