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mariarad [96]
3 years ago
12

What are the products of the combustion of a hydrocarbon?

Chemistry
2 answers:
Oxana [17]3 years ago
7 0

Answer:

I think carbon and hydrogen

KiRa [710]3 years ago
4 0

Answer:

products formed after combustion of a hydro carbons are :

  • =》 carbon dioxide
  • =》water

example;

CH4 + 2O2 -》CO2 + 2H20 + heat

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use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a vel
My name is Ann [436]

Answer:

7.7439×10⁻³¹ m

Explanation:

The expression for Heisenberg uncertainty principle is:

\Delta x\times \Delta v=\frac {h}{4\times \pi\times m}

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

\Delta x\times 0.1=\frac {6.62\times 10^{-34}}{4\times \frac {22}{7}\times 0.68\times 10^{-3}}

<u>Δx = 7.7439×10⁻³¹ m</u>

8 0
3 years ago
Find errors in this equation. Ca(s) + water(l) -&gt; C(OH)2 (aq) + H(6)
vladimir1956 [14]
Calcium (s) + h2o (i) -> carbon(oh)2 (AQ) +h(6)
well aq isnt a element.  
4 0
3 years ago
I GIVE BRAINLIEST TO WHO EVER GETS IT RIGHT!
Gala2k [10]

Answer: B. Bohr and  D. Rutherford

6 0
3 years ago
How do the methods of scientist lead to knowlodge
Nikitich [7]

Answer:

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Explanation:

6 0
2 years ago
Read 2 more answers
The reaction of 9.2 grams of fluorine with excess chlorine produced 6.3 grams of clf3. what percent yield of clf3 was obtained?
andrey2020 [161]

Answer:

              %age Yield  =  20.12 %

Solution:

The Balance Chemical Reaction is as follow,

                                          Cl₂  +   3 F₂    →    2  ClF₃

According to Equation ,

              114 g (3 mole) F₂ produces  =  184.88 g (2 moles) of ClF₃

So,

                       19.2 g of F₂ will produce  =  X g of ClF₃

Solving for X,

                      X =  (19.2 g × 184.88 g) ÷ 114 g

                      X  =  31.13 g of ClF₃   (Theoretical Yield)

As we know,

                     %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

                     %age Yield  =  (6.3 g ÷ 31.3 g) × 100

                     %age Yield  =  20.12 %

5 0
3 years ago
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