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Zina [86]
3 years ago
12

If 15.60 g of a hydrated compound is heated in an oven for several hours, its mass drops to 8.63 g. Assuming that the reduction

in mass is due to loss of water, what is the percentage of water in the original hydrate?
Chemistry
2 answers:
Ber [7]3 years ago
6 0
In order to calculate the percent of water in the hydrate, we need to know the amount of water that is lost after heating. We simply subtract the initial amount and the final amount. We do as follows:

mass of water = 15.60 g - 8.63 g = 6.97 g

Percent water = 6.97 / 15.60 x 100 = 44.68%
puteri [66]3 years ago
6 0
Mass of water = 15.60 g - 8.63 g = 6.97 g

Percent water = 6.97 / 15.60 x 100 = 44.68%
Good Luck, I hope this helps you!! :)
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Xenon forms several compounds with oxygen and fluorine. It is the most reactive non-radioactive noble gas because a. its large r
muminat

Answer:

d. its effective nuclear charge is lower than the other noble gases.

Explanation:

Xenon belongs to group O on the periodic table. Most of the elements here are unreactive.

Due to the large size of Xenon, the outermost electrons have very low effective nuclear charge. Effective nuclear charge is the effect of the positive charges of the nucleus on the electrons in orbits. This effect decreases outward as atomic shell increases.

Xenon has a very large atomic radius and there is weak a nuclear charge on the outermost electrons. The more electronegative elements would be able to attract some of its outermost electrons easily and form chemical bonds with xenon much more readily.

7 0
3 years ago
Molecules are large atoms true or false
Naddik [55]

Answer:

False

Explanation:

Molecules are not more sizable atoms than the average atom. Molecules are compunds of two different symbolic elements, when you combine then you get a molecule. The answer to your question is false because if they were larger molecules, they would be in object around us but molecules are not in all objects around us.

7 0
3 years ago
Jamie rolls a 6-sided die 30 times and determines that the experimental probability of rolling a 2 is Start Fraction 1 over 15 E
anyanavicka [17]

Answer:

Conduct more trials

Explanation:

Theoretical Probability can be defined as what someone is expecting to happen

Experimental Probability on the other hand, is defined as what actually happens.

Probability is usually calculated in the same way for experimental probability and that of theoretical probability. You divide the total number of possible ways in which a particular outcome can happen, by the total number of outcomes itself.

In Experimental probability, the more times a probability is tried, it gets closer and even more closer to theoretical probability.

So, for the question, Jamie should improve the number of tries more, so as to get his experimental probability results to be closer to the theoretical probability result.

8 0
3 years ago
If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?
kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

P(\%) =  \frac{0.1}{0.7}  \times 100 \\  = 14.285714...

We have the final answer as

<h3>14.29 %</h3>

Hope this helps you

4 0
3 years ago
Calculate the molar mass of a gas
spin [16.1K]

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

n=\frac{PV}{RT}

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

n=\frac{1\times .280}{0.08205\times 273}

n = 0.0125 moles

Now n=\frac{given\ mass}{Molar\ mass}

Molar\ mass=\frac{given\ mass}{n}

given mass = 0.4 g (given)

Molar\ mass=\frac{0.4}{0.0125}

On solving we get:

Molar mass = 32 g/mol

4 0
3 years ago
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