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Zina [86]
3 years ago
12

If 15.60 g of a hydrated compound is heated in an oven for several hours, its mass drops to 8.63 g. Assuming that the reduction

in mass is due to loss of water, what is the percentage of water in the original hydrate?
Chemistry
2 answers:
Ber [7]3 years ago
6 0
In order to calculate the percent of water in the hydrate, we need to know the amount of water that is lost after heating. We simply subtract the initial amount and the final amount. We do as follows:

mass of water = 15.60 g - 8.63 g = 6.97 g

Percent water = 6.97 / 15.60 x 100 = 44.68%
puteri [66]3 years ago
6 0
Mass of water = 15.60 g - 8.63 g = 6.97 g

Percent water = 6.97 / 15.60 x 100 = 44.68%
Good Luck, I hope this helps you!! :)
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PIT_PIT [208]
Reaction of Acyl Halides with Grignard reagent results in the formation of Ketones in first step. While in second step reaction of Grignard reagent with Ketones results in the formation of Tertiary Alcohols.

If you want to stop the reaction at Ketone stage then you are required to use another mild reactive organometallic compound. In our case we will use Organocuprates. Organocuprates are also known as Gilman Reagents. These reagents does not add to ketones, aldehydes and esters but they can add to acid halides to produce Ketones.

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3 years ago
When an electron passes through the magnetic field of a horseshoe magnet, the electron's?
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When an electron passes through the magnetic field of a horseshoe magnet, the electron's direction is changed.

Path of an electron in a magnetic field

The force (F) on wire of length L carrying a current I in a magnetic field of strength B is given by the equation:

F = BIL

But Q = It and since Q = e for an electron and v = L/t you can show that :

Magnetic force on an electron = BIL = B[e/t][vt] = Bev where v is the electron velocity

In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.

Therefore :

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and so you can see from these equations that as the electron slows down the radius of its orbit decreases.

If the electron enters the field at an angle to the field direction the resulting path of the electron (or indeed any charged particle) will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.

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4 0
1 year ago
What is the value of the activation energy of the uncatalyzed reaction? Express your answer to three significant figures and inc
goblinko [34]

Answer:

175 kJ

Explanation:

Activation energy can be defined as the potential energy that is needed to change reactants to products. This is the minimum energy required for the chemical reaction to take place. Thus, using the given figure:

Activation energy = activation complex - reactant energy

In the given figure, activation complex = 400 kJ

reactant energy = 225 kJ

Therefore:

Activation energy = 400 - 225 = 175 kJ

3 0
3 years ago
Read 2 more answers
When a tip of a plant is cut it doesn't grow well​
aleksandr82 [10.1K]

Explanation:

the tip of a growing plant contains special rapidly diving cells called apical meristem ,these cells are responsible for increase in the length of the plant . if we cut out these cells ,length growth of the plant will be stunned as these cells are not present anyplace else.

8 0
2 years ago
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Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
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