Answer:
t / τ₀ = 2.9
the time constant has to be multiplied by approximately three
Explanation:
The expression for long of a capacitor is
q = q₀ (1- e (-t/τ₀)
Where q is the charge and τ₀ is the time constant. What is found for when the initial capacitor charge at 63.5% (e⁻¹) of the maximum charge
In our case we are asked that the load be 94.5%, this means that
q/q₀ = 94.5%
q/q₀ = 0.945
Let's replace and calculate
q/q₀ = 1 - e (-t/τ₀)
0.945 = 1 - e (-t/τ₀)
(-t /τ₀) = ln (1 -0.945) = ln (0.055)
t / τ₀ = 2.9
the time constant has to be multiplied by approximately three for this charge
The change in internal energy that accompanies the transfer of heat, q, or work, w, into or out of a system can be calculated using the following equation: Note the value of heat and work as they are transferred into or out of a system.
Explanation:
What do we call a word that tells about an action ?
Each of the three choices is tasteless, exhibitionist, juvenile, and dangerous. John should do none of them.
Encountering a news crew, there's no reason for John to call attention to himself in a childish way, or interfere with their work in <em>any</em> way.
What he <u><em>should</em></u> do is:
==> Slow down
==> Pass the scene cautiously
==> Resume his normal, legal speed quietly, in case the crew happens to be recording audio at the moment.
Mysteriously, this course of action is nowhere to be found among the choices listed.
Answer:
The only way to increase the work output is to increase the work input. You can't get more work out of a machine than you put into it. The moving parts of a machine must use some of the work input to overcome friction. Because of friction, the work output of a machine is always less than the work input.
Explanation:
