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3 years ago

6

Which of the following statements about igneous rocks is correct?

1 answer:

g100num [7]3 years ago

3 0

Although you have not provided the possible answers, igneous rocks are formed out of magma or lava, with or without crystals, and they can be found either on the surface or under it. This is a basic description of the type of rocks, so it might fit some of the answers you may have.

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A force of 500 N is exerted on a baseball by the bat for 0.001 s. What is the change in momentum of the baseball?

GarryVolchara [31]

Answer: Δp = F*Δt = 500N*0.001s = 0.5Ns

3 0

3 years ago

Investigate the relationship between volume and pressure of a gas at a constant temperature.

sveta [45]

Gay Lussac's Law states: At a constant volume Pressure<span> divided by </span>Temperature<span> is</span>constant<span> P/T = k Together these three laws form the foundation of the Ideal </span>Gas<span>Law. Objective: Students will </span>investigate<span> Gay Lussac's Law relating </span>pressure<span> and</span>temperature<span> at a </span><span>constant temperature.</span>

7 0

3 years ago

Calculate the minimum amount of work needed to move a 500-kg rocket payload from Earth's surface to the ISS in orbit 400,000m ab

WINSTONCH [101]

Answer:

2.000.000.000

Explanation:

Apply the formula:

Work = Force . Displacement

W = 500.10 . 400.000 (the 10 come from gravity)

W = 5000 . 400.000

W = 2.000.000.000 Joules

I think it is that, can be wrong.

7 0

2 years ago

A department store sells an ""astronomical telescope"" with an objective lens of 30 cm focal length and an eyepiece lens of foca

Yuliya22 [10]

Answer:

The magnifying power of this telescope is (-60).

Explanation:

Given that,

The focal length of the objective lens of an astronomical telescope, $f_o=30\ cm$

The focal length of the eyepiece lens of an astronomical telescope, $f_e=5\ mm=0.5\ cm$

To find,

The magnifying power of this telescope.

Solution,

The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :

$m=\dfrac{-f_o}{f_e}$

$m=\dfrac{-30}{0.5}$

m = -60

So, the magnifying power of this telescope is 60. Therefore, this is the required solution.

7 0

2 years ago

A distance of 200 ft must be taped in a manner to ensure a standard deviation smaller than ± 0.04 ft. What must be the standard

Nutka1998 [239]

Answer:

The error in tapping is ±0.02828 ft.

Explanation:

Given that,

Distance = 200 ft

Standard deviation = ±0.04 ft

Length = 100 ft

We need to calculate the number of observation

Using formula of number of observation

$n=\dfrac{\text{total distance}}{\text{deviation per tape length}}$

Put the value into the formula

$n=\dfrac{200}{100}$

$n=2$

We need to calculate the error in tapping

Using formula of error

$E_{series}=\pm E\sqrt{n}$

$E=\dfrac{E_{series}}{\sqrt{n}}$

Put the value into the formula

$E=\dfrac{0.04}{\sqrt{2}}$

$E=\pm 0.02828\ ft$

Hence, The error in tapping is ±0.02828 ft.

3 0

3 years ago