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nevsk [136]
3 years ago
12

John owns a used 2003 mustang Mach 1, he spots a news crew with a bunch of people what should he do? A) Rev his engine at the hi

ghest RPM B) Do a burnout C) Drive near the Crowd and drop a gear and hurl into the crowd D) ALL OF THE ABOVE
Physics
1 answer:
Marta_Voda [28]3 years ago
5 0

Each of the three choices is tasteless, exhibitionist, juvenile, and dangerous.  John should do none of them.

Encountering a news crew, there's no reason for John to call attention to himself in a childish way, or interfere with their work in <em>any</em> way.

What he <u><em>should</em></u> do is:

==> Slow down

==> Pass the scene cautiously

==> Resume his normal, legal speed quietly, in case the crew happens to be recording audio at the moment.

Mysteriously, this course of action is nowhere to be found among the choices listed.

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Turning a magnet very quickly would be BEST used to create A) radiation. Reactivate B) light waves. Reactivate C) an electric cu
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<h2>Answer:</h2>

<u>Turning a magnet very quickly would be BEST used to create an electric current</u>

<h2>Explanation:</h2>

In Electromagnetic waves electric field produces magnetic field and vice versa. A moving magnet can produce electric current. Dynamo is the best example for it. In dynamo armature is rotated between the magnets which results in the development of electric field and hence an electric current is produced in it.

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If an object's velocity changes from 25 meters per second to
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B

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The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i
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3 years ago
If an object absorbs all colors but red, we see
julia-pushkina [17]
[I researched for you, since I am not in that particular level to know that knowledge yet. I assure this is accurate info :)]

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Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5
pishuonlain [190]

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

\dfrac{F}{L}= \dfrac{KI_1I_2}{d}

I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}

I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}

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distance where the magnetic field is zero

\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}

y_1 = 0.248\ m

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

3 0
3 years ago
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