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4 years ago

The answer please!!!

Physics

1 answer:

Tomtit [17]4 years ago

8 0

Ahhh ! Tricky tricky question !

All of the books are just sitting there, "RESTING" on the table. They're not slipping, sliding, rising, falling, rolling, swinging, swooshing, wandering, strolling, or meandering. Just "RESTING" in their stack.

None of the books has a changing speed or direction of motion. So none of the books is experiencing any acceleration.

So the NET FORCE on any book must be zero.

Pick a book. It doesn't matter whether you picked the bottom, middle, or top book. And the book's mass, weight, color, age, author, cost, or topic also don't make any difference. If the book is not accelerating, then the NET FORCE on it is zero. Just ask Dr. Newton. He'll tell you "F = m A" .

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450 nm of light falls on a single slit of width 0.30 mm. What is the angular width of the central diffraction peak

Andre45 [30]

Angular width is 3 x 10^-3

Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,

where λ is wavelength

Given:

λ = 450 nm = 450×10^−9m

d = 0.3x10^−3m, D = 1m

W = 2 x 450×10^−9/0.3x10^−3*1

To Find:

Angular width

Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima

θ = W/D

θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3

Hence, angular width is 3 x 10^-3

Learn more about Angular width here:

brainly.com/question/25292087

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4 0

2 years ago

A 10.00 kg mass is moving to the right with a velocity of 14.0 m/s. A 12.0 kg mass is moving to the left with a velocity of 8.00

Basile [38]

Answer:

2 m/s

Explanation:

From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.

Let the 10.00 kg mass be $m_1$ and the 12.0 kg mass be $m_2$ . When they collide and stick, they have a combined mass of $m_1+m_2$ .

Momentum is given by $p=mv$ . Set up the following equation:

$\displaystyle m_1v_1+m_2v_2=(m_1+m_2)v_f$ , where $v_f$ is the desired final velocity of the masses.

Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.

Solving yields:

$10\cdot 14 + 12\cdot (-8)=(10+12)v_f\\\implies v_f=\boxed{2 \text{ m/s}}$

4 0

2 years ago

Pls help I will give brainlist and don’t give me a link I can’t open them

dezoksy [38]

Answer:

200

Explain:

I have a big brain

5 0

3 years ago

What happen when the rest of the container is filled with water?

7nadin3 [17]

Nothing will happen. The mercury and steel will not move. It’s just like filling a glass halfway with cement and then pouring water on top of it.

6 0

2 years ago

Read 2 more answers

The satellite s travels around the earth in a circular path with a constant speed of 20 mm>h. If the acceleration is 2.5 m&gt

Zanzabum

Answer:

The altitude of planet = 5989.198 km

Explanation:

We know that centripetal acceleration, $a = v^2/r$ , where v is the velocity and r is the radius. In this case both acceleration and velocity is given, so we can find radius of satellite.

v = $20 Mm/hr = 20*10^6/3600 = 5555.56 m/s$

a = $2.5 m/s^2$

So, $2.5 = 5555.56^2/r\\ \\ r = 12345698.77 m = 12345.698km$

We have diameter of earth = 12713 km

Radius of earth = 12713/2 = 6356.5 km

The altitude of planet = Radius of planet - radius of earth

= 12345.698 - 6356.5

= 5989.198 km

8 0

3 years ago