Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

Let the rate of growing each year be g.

After 6 years height of tree = 4 + 6g

After 4 years height of tree = 4 + 4g

At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

That is

$4+6g=4+4g+\frac{4+4g}{5}\\\\4+6g=\frac{20+20g+4+4g}{5}\\\\20+30g=24+24g\\\\6g=4\\\\g=\frac{2}{3}ft/year$

Option D is the correct answer.

8 0

3 years ago

Please help with this

KonstantinChe [14]

I believe the answer is 32

4 0

3 years ago

Write a problem that involves finding the unknown measure of a side of a rectangle include the solution?

tankabanditka [31]

Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters

7 0

2 years ago