The answer it b your welcome
I don't get you but if you transform the equation to it's standard form, it will be
3x+4y=4
First, Multiply each term by 4:
y(4)=-3x/4(4)+1(4)
4y=-12x/4+4
4y=-3x+4
Now add 3x to both sides of the equation:
4y+3x=-3x+3x+4
3x+4y=0+4
3x+4y=4
Answer:
Divide them by the same number
Step-by-step explanation:
14/2=7
10/2= 5
y7/y5
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
