We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
The answer would actually be B.) S
As you can see, where the S is, it is in the same position as the A on the other triangle.
Answer:
x=-1
Step-by-step explanation:
54x+64=49x+59
subtract 64
54x=49x-5
subtract 49x
5x=-5
divide by 5
x=-1
Answer:
-20
Step-by-step explanation:
when you solve: -7u-7=7, you get u= -2 and when you plug it in you get this equation 9(-2)-2=?
then you get -20
