Answer: A concave mirror focuses rays of light
Explanation:
Answer:
Explanation:
Comment
You have to read this carefully enough that you don't mix up energy and forces.
Gravity is a force. If you don't believe me try jumping off a building. Which way are you going to go and why? Down because gravity attracts your mass.
So Magnetism must be a force as well. It acts in one direction, but not a specific one the way gravity acts). It also either attracts or repulses (pushes an object away)
Answer A
Answer:
Explanation:
change in flux = no of turns x area of coil x change in magnetic field
= 163 x π 2.65² x 10⁻⁴ x ( .481 - 0 )
= 1728.84 x10⁻⁴ weber
rate of change of flux = change in flux / time
= 1728.84 x10⁻⁴ / .149
= 11603 x10⁻⁴ V .
volt induced = 1.16 V
current in the circuit
= volt induced / resistance
1.16 / 10.7 = .1084 A
energy dissipated = i²Rt where i is current , R is resistance and t is time.
= .1084² x 10.7 x .149
= .018734 J
= 18.73 mJ .
Answer:
F=(-4.8*10^22,0,0) N
Explanation:
<u>Given :</u>
We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°
Solution :
We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.
The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next
F=|F|cosФp (1)
Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet
F=|F|cosФp
=-4.8*10^22 N*p
<em>As this force is in one direction, we could get its vector as next </em>
F=(-4.8*10^22,0,0) N
F=(0,-4.8*10^22,0) N
F=(0,0-4.8*10^22) N
The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.
