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Furkat [3]
3 years ago
13

A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from

equilibrium, what is its instantaneous velocity?
Physics
1 answer:
kaheart [24]3 years ago
6 0

Answer:

zero

Explanation:

In this system, only conservative forces act. Therefore, the mechanical energy, that is, the sum of the kinetic energy and the potential energy, remains constant. When the mass is at its maximum displacement from equilibrium, its potential energy is maximum, therefore, its kinetic energy is minimal, that is to say, that its instantaneous velocity at that point is zero.

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For each of the cases listed below, decide whether or not the motion described is an example of acceleration: (T/F)
scoundrel [369]

Answer:

1. True

2. True

3. False

4. False

5. True

6. False

Explanation:

Acceleration: It refers to the change in velocity/speed of an object with respect to time. When the speed increases with time we call it acceleration and when its decreases it is called as deceleration.  Let us analyze each instance individually:

1. When roller coaster starts to roll down the track its speed will increase with time. That means it is accelerating.

2. When the ball reaches at the peak of its trajectory, it comes to a stop for a fraction of a second that means it decelerates.

3. Since the velocity remains constant there is no acceleration.

4. Since the speed is no changing with time, there is no acceleration.

5. Since the moving plane comes to a stop, it is a case of deceleration.

6. Since the truck is moving at a constant speed so the acceleration is zero.

8 0
4 years ago
If the force between two fixed Charged spheres is F and you triple the charge on one sphere and also triple the distance between
mezya [45]
Since the charge has a direct proportionality, the increase will be a factor of three. But, since you triple the distance, which has an inversely squared proportion, it will be 3/9 F or 1/3 F.

*This is all based on the fact that this is true:
F_s = \frac{Kq_1q_2}{r^2}

4 0
4 years ago
A Venturi tube may be used as the inlet to an automobile carburetor. If an inlet pipe with a diameter of 2.0 cm diameter narrows
valkas [14]

Answer:

I think it's  81

4 0
4 years ago
Read 2 more answers
What is the weight of an object when the object has a mass of 22kg
Savatey [412]
Assuming the object is on earth the objects weight would be equal to its mass multiplied by the gravitational field constant

mass=22kg
g=9.80665N/kg

weight=(22 kg) (9.80665 N/kg)=215.7463N

generally g is rounded to be 10 N/kg so for any question where it asks the weight given the mass just multiply by 10 and that should suffice. In this case the answer would be 220 N
5 0
3 years ago
in mammal the weight of the heart approximately 0.5% total body weight write linear model that gives the heart weight in terms o
maks197457 [2]

Let the total weight of the body be = x

Let the weight of the heart of the mammals be = y

Now the given percentage of 0.5 %, we will convert it into decimal form,

so this is equal to 0.005 in decimal form,


so the linear equation that gives the heart weight in terms of body weight will be,

y = 0.005x


7 0
3 years ago
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