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Alla [95]
3 years ago
12

A bugle can be thought of as an open-end pipe. If a bugle were straightened out, it would be 2.65 m long. a. If the speed of sou

nd is 343 m/s, find the lowest frequency (i.e., the largest wavelength) that can resonate in a bugle. (64.72 Hz) b. Find the next two higher resonant frequencies in the bugle. What harmonics are they
Physics
1 answer:
vitfil [10]3 years ago
5 0

Answer

given,

Length of pipe, L = 2.65 m

speed of sound, v = 343 m/s

Pipe is open end Pipe

a) Lowest frequency

  condition, for open end pipe

     \lambda_1 = 2 L

     \lambda_1 = 2\times 2.65  

     \lambda_1= 5.30 m

   For lowest frequency

    f_1 = n\dfrac{v}{\lambda_1}

     n = 1

    f_1 = \dfrac{343}{5.30}

           f₁ = 64.72 Hz

b) For second frequency in bugle

        n = 2

   f_2 =2\times \dfrac{343}{5.30}

          f₂ = 129.43 Hz

   for n = 3

   f_3 =3\times \dfrac{343}{5.30}

          f₃ = 194.16 Hz

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A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle
dangina [55]

Answer:

40.0⁰

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The formula for calculating the magnetic flux is expressed as:

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Given

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4 0
2 years ago
Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti
Alex

Answer:

A) The speed of the water must be 8.30 m/s.

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Total kinetic energy created by this maneuver:

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