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svetoff [14.1K]
3 years ago
10

Which constants and directions always apply when using gravity?​

Physics
2 answers:
Lostsunrise [7]3 years ago
6 0

Answer:

.

Explanation:

Romashka-Z-Leto [24]3 years ago
3 0

Answer:

Explanation::

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The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at ????????,2=17.9vi,2=17.9
AleksAgata [21]

Answer:

V=27.24 m/s

Explanation:

We need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_{f}\\

The velocity of the eagle its defined by its two components:

v_x=V*cos(\theta)\\v_y=V*sin(\theta)\\v_x=35.9*cos(61.9^o)=16.9m/s\\v_y=35.9*sin(61.9^o)=31.7m/s

2*(16.9m/s(i)+31.66m/s(j))+17.9m/s(i)=3*v_f\\v_f=17.23m/s(i)+21.10m/s(j)

because speed is a scalar value:

V=\sqrt{(21.10m/s)^2+(17.23)^2}\\V=27.24m/s

6 0
3 years ago
The space shuttle orbits 310 km above the surface of the Earth.
MAVERICK [17]

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

F=G\frac{mM}{r^2}

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

m=5.0 kg is the mass of the sphere

M=5.98\cdot 10^{24} kg is the Earth's mass

R=6370 km is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

r=6370 km+310 km=6680 km=6.68\cdot 10^6 m

Substituting into the equation, we find

F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N

8 0
3 years ago
For this problem, we assume that we are on planet-i. the radius of this planet is r =4200 km, the gravitational acceleration at
Minchanka [31]
The expression commonly used for potential gravitational energy is just simplification. It is actually just the first term in Taylor expansion of the real expression. 
In general, the potential energy of gravitational field is defined as:
U=-G \frac{mM}{r}
Where G is universal gravitational constant, and r is the distance between the objects centers of mass. Negative sign represents the bound state.
Since we are not given the mass of the planet we have to calculate it.
F_g=G\frac{mM}{r_p^2}\\ mg=G\frac{mM}{r_p^2}\\ g=G\frac{M}{r_p^2}
This formula can be used for any planet. It gives you the gravitational acceleration on the planet's surface. We can use it to calculate the planet's mass:
g=G\frac{M}{r_p^2}\\ M=\frac{gr_p^2}{G}=2.41\cdot 10^{24}kg
Now we can calculate the potential energy of that cannonball when it reaches its maximum height.
U=-G \frac{mM}{r}\\ U=-G \frac{mM}{r_p+h}
When we plug in the numbers we get:
U=-4.99\cdot 10^{10} J
The potential energy has to be equal to the kinetic energy.
E_k=4.99\cdot 10^{10} J

3 0
3 years ago
Tốc độ v của một vật được cho bởi phương trình v = At
ki77a [65]

If <em>v(t)</em> is speed measured in meters per second (m/s), and <em>t</em> is time measured in seconds (s), then the constants <em>A</em> and <em>B</em> in

<em>v(t)</em> = <em>At</em> ³ - <em>Bt</em>

must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.

[m/s] = <em>A</em> [s]³ - <em>B</em> [s]

[m/s] = [m/s⁴] [s]³ - [m/s²] [s]

[m/s] = [m/s] - [m/s]

[m/s] = [m/s]

5 0
2 years ago
Physical Science<br> convert 5.3 hl to dal
Nikitich [7]

Answer: 53 dal

Explanation: 5.3x10=53, to get dal you have to multiply by 10 to get 5.3x10=53.

Hope this helped! Please mark Brainliest!

3 0
2 years ago
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