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Triss [41]
3 years ago
11

8x4+2x3-7x2+3x-2 divided by 4x2-x-1

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

The answer is  -x + 20

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2. Factor completely: f(x) = x4 - 6x2? – 27
VladimirAG [237]

Answer:

sorry don't know answer

6 0
3 years ago
In square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC. What is the ratio of the area of tria
ipn [44]

Answer:

1:8

Step-by-step explanation:

Given that in square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC.

Let the side of the square be a.

Area of square ABCD = a^2

The triangle AMN is having two legs of a right triangle as half of side of the square

i.e. Triangle AMN has base = height = a/2

So area of triangle AMN = \frac{1}{2} bh\\=\frac{a^2}{8}

Ratio of the area of triangle AMN to area of square ABCD

= 1:8

6 0
3 years ago
Show all work and receive brainliest!
Svet_ta [14]

Answer:

Lower Quartile: 62

Upper Quartile: 81

Interquartile Range: 19

Step-by-step explanation:

To find the lower quartile, you want to find the median from the minimum to the median.

49, 55, 62, 64, 67

The median of this is 62. Therefore, 62 is the lower quartile.

To find the upper quartile, you want to find the median from the median to the maximum.

76, 79, 81, 82, 83

The median of this is 81. Therefore, 81 is the upper quartile.

To find the interquartile range, you subtract the upper and lower quartile.

81-62=19

The difference is 19. Therefore, the interquartile range is 19.

5 0
4 years ago
Lesson 20 5h grade homework
LUCKY_DIMON [66]
1igjgjyuhr55cysrhgu8rsyggshrborbgxm
5 0
3 years ago
4 of 4 Find the area of the shape below. Give your answer in terms of T. 4cm 32cm The diagram is not drawn to scale. 8cm​
andrey2020 [161]

The answer is 176π cm².

Given shape is a combination of 3 semi-circles.

And we need to find the area of the colored region.

The diameter of the biggest semi-circle is 32 cm.

Let d₁, and r₁ denote the diameter and radius of the biggest semi-circle respectively.

⇒ d₁ = 32 cm and r₁ = 32/2 = 16

The diameter of the smallest semi-circle is 4cm.

Let d₂, and r₂ denote the diameter and radius of the smallest semi-circle.

⇒ d₂ = 4 cm and r₂ = 4/2 = 2

Let d₃, and r₃ denote the diameter and radius of the middle semi-circle.

From the diagram, the diameter of the middle semi-circle is,

d₃ = d₁ - (d₂ + 8) = 32 -(4 + 8) = 32 - 12 = 20

⇒ d₃ = 20 cm and r₂ = 20/2 = 10

The area of a semi-circle is given by the formula πr²/2, where r is the radius.

Let A₁ denote the area of the biggest semi-circle.

Then A₁ = π(r₁)²/2 = π × (16)² / 2 = 256π/2 = 128π cm²

Let A₂ denote the area of the smallest semi-circle.

Then A₂ = π(r₂)²/2 = π × (2)² / 2 = 4π/2 = 2π cm²

Let A₃ denote the area of the middle semi-circle.

Then A₃ = π(r₃)²/2 = π × (10)² / 2 = 100π/2 = 50π cm²

Therefore, the area of the colored region is A₁ + A₃ - A₂

= 128π + 50π - 2π

= 176π cm²

Learn more at:

brainly.com/question/19581549

#SPJ9

8 0
2 years ago
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