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Anastasy [175]
3 years ago
12

How do I find the side lengths for this triangle if only one side and ond angle is given? Plz help

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0
The two unknown sides are equal to each other so then the two unknown angles are also equal.

A triangle angles add up to 180
36 + 2x = 180
2x = 180 - 36
2x = 144
unknown angles x = 72°

draw line down center of triangle to make two right triangles with side 22/2 = 11. SOH CAH TOA

cos(72) = 11/H
H = 11/cos(72)
H = 35.6

perimeter = 22 + 2(35.6)
perimeter = 93.2 cm

answer E .



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Julli [10]

Answer:

A. Miguel has the greatest spread.

The range of the two persons can be determined by:

Adam's range = 106 -91 = 15

Miguel's range = 105 -86 = 19

B. Considering the middle 50% of the training time, the person with the least spread is Adam.

Adam - 103 105 104 106 100

Miguel - 88 86 89 93 105

Adam's 50% range = 106 - 100 = 6

Miguel's 50% range = 105 - 86 = 19

Adam has the least spread

C. Miguel is inconsistent with the time set for training compared to that of Adam.

The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.

3 0
4 years ago
If Natalie walked 3/5 in 1/2 hour, how fast did she walk, in miles per hour?
melisa1 [442]
She walked .6 mph because 3/5 x 2= 6/10
1/2 x 2=1

6 0
3 years ago
If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?​
Oduvanchick [21]

\large\underline{\sf{Solution-}}

<u>Given:</u>

\rm \longmapsto x = a \sin \alpha  \cos \beta

\rm \longmapsto y = b \sin \alpha  \sin \beta

\rm \longmapsto z = c\cos \alpha

Therefore:

\rm \longmapsto \dfrac{x}{a}  = \sin \alpha  \cos \beta

\rm \longmapsto \dfrac{y}{b}  = \sin \alpha  \sin \beta

\rm \longmapsto \dfrac{z}{c} = \cos \alpha

Now:

\rm =  \dfrac{ {x}^{2} }{ {a}^{2}} +  \dfrac{ {y}^{2} }{ {b}^{2} } +  \dfrac{ {z}^{2} }{ {c}^{2} }

\rm =  { \sin}^{2} \alpha  \cos^{2}  \beta   +  { \sin}^{2} \alpha  \sin^{2} \beta  +  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha  (\cos^{2}  \beta   +  \sin^{2} \beta  )+  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha \cdot1+  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha + { \cos}^{2} \alpha

\rm = 1

<u>Therefore:</u>

\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} +  \dfrac{ {y}^{2} }{ {b}^{2} } +  \dfrac{ {z}^{2} }{ {c}^{2} }  = 1

5 0
3 years ago
Describe a diagram of a pair of triangles that share a common angle and a common side.
Delicious77 [7]

Answer:

uploaded in the attachment

Step-by-step explanation:

  • if u see the diagram, there are 2 triangles in it ABC and ABD.
  • the common side for these pair of triangles is AB.
  • common angle is angle BAC.
  • therefore, these triangles share a common side AB and a common angle BAC.

7 0
3 years ago
According to the census data, in 2014 about 126 million adults in the United States were women, which is about 51.4% of the tota
jeka57 [31]

Answer:

245.1361868

Step-by-step explanation:

126               51.4

___    =        ____             126x100=12600      12600/51.4=245.1361868

 x                  100

6 0
3 years ago
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