Answer:
Answer is in attached image!
Explanation:
A good website to learn coding is called Lynda.com. It costs money but its well worth it!
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Physical parts of computer: Computer Hardware
Answer:
<u>B) Throwable</u>
Explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
There are a wide range of classes on the exception class hierarchy. All the way on the top is the Objects Class but since that is not an available answer we will move on to the next one. The next one is the <u>Throwable</u> class. therefore that is the answer.
**Exception is after Throwable , and Arithmetic Exception is at the bottom.... everything is a class so that is not a part of the hierarchy **
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.