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Law Incorporation [45]
3 years ago
5

-7a⁵· 6a write the product in simplest form ?

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

= -42a⁶

Step-by-step explanation:

-7a⁵. 6a = -7a⁵ × 6a

Therefore;

We multiply; -7 × 6 = -42

then; a⁵ × a = a⁶

Thus; we have -42 a⁶

Hence; <u>-7a⁵ × 6a = -42 a⁶</u>

Flura [38]3 years ago
7 0

Answer:

-42a⁶ is the answer.

Step-by-step explanation:

we have given  the expression:

-7a⁵· 6a

we have to write this product in its simplest form

To write it in simplest form we use the formula mentioned below :

xᵃ .  xᵇ = x ᵃ⁺ᵇ

using above fomula we have:

(-7)(6)a⁽⁵⁺¹⁾

-42a⁶ is the product in simplest form.

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Suppose theta is an angle in the standard position whose terminal side is in quadrant 4 and cot theta = -6/7. find the exact val
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First off, let's notice that the angle is in the IV Quadrant, where sine is negative and the cosine is positive, likewise the opposite and adjacent angles respectively.

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\bf cot(\theta )=\cfrac{\stackrel{adjacent}{6}}{\stackrel{opposite}{-7}}\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{6^2+(-7)^2}\implies c=\sqrt{36+49}\implies c=\sqrt{85} \\\\[-0.35em] ~\dotfill

\bf tan(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{adjacent}{6}} ~\hfill csc(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{opposite}{-7}} ~\hfill sec(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{adjacent}{6}} \\\\\\ sin(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{sin(\theta)=\cfrac{-7}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies sin(\theta)=-\cfrac{7\sqrt{85}}{85}}

\bf cos(\theta)=\cfrac{\stackrel{adjacent}{6}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{cos(\theta)=\cfrac{6}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies cos(\theta)=\cfrac{6\sqrt{85}}{85}}

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3 years ago
Nina ran 2.5 miles in 20 minutes at the same pace how long would it take her to run 6 miles
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nirvana33 [79]
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<span>dy/dx = dy/dt  *   dt/dx             dy/dt = -2
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The picture below shows a box sliding down a ramp:
Gennadij [26K]

Answer:

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sin(68\°)=\frac{14}{AC}

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AC=15.1\ ft

4 0
3 years ago
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