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Law Incorporation [45]
3 years ago
5

-7a⁵· 6a write the product in simplest form ?

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

= -42a⁶

Step-by-step explanation:

-7a⁵. 6a = -7a⁵ × 6a

Therefore;

We multiply; -7 × 6 = -42

then; a⁵ × a = a⁶

Thus; we have -42 a⁶

Hence; <u>-7a⁵ × 6a = -42 a⁶</u>

Flura [38]3 years ago
7 0

Answer:

-42a⁶ is the answer.

Step-by-step explanation:

we have given  the expression:

-7a⁵· 6a

we have to write this product in its simplest form

To write it in simplest form we use the formula mentioned below :

xᵃ .  xᵇ = x ᵃ⁺ᵇ

using above fomula we have:

(-7)(6)a⁽⁵⁺¹⁾

-42a⁶ is the product in simplest form.

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Please answer the question, I think I have the answer but I'm not sure.
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Answer:

20cm

Step-by-step explanation:

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3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
3 years ago
Help me please???!!!!!!!
Zolol [24]

Answer:

im not sure

go on volume calculator

Step-by-step explanation:

5 0
3 years ago
Evaluate the expression. –5g – 6 for g = –2
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- 5g - 6
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3 years ago
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