the factors of 33 are 1, 3, 11, 33
the factors of 88 are 1, 2, 4, 8, 11, 22, 44, 88
so the greatest common factor is 11
Answer:
42.9
Step-by-step explanation:
There are many ways to answer this one, the most direct way would be to state that tan(65)=a/20
20tan(65)=a
Using the calculator (set in degree mode)
we find that a ~ 42.9
I'm pretty sure it C since line L and line M are parallel
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal(
)
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P(
>
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
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Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.