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4 years ago

Which statement correctly explains the molecular structure of water?

2 answers:

6 0

The statement that correctly explains the molecular structure of water is A. One oxygen (O) and two hydrogen atoms (H2) are joined by a covalent bond.
It cannot be ionic, since ionic bonds tend to be sold at room temperature.

nata0808 [166]4 years ago

5 0

A water molecule can form four hydrogen bonds by accepting two hydrogen atoms and donating two hydrogen atoms.
Thus,
One oxygen and two hydrogen atoms are joined by a covalent bond correctly explains the molecular structure of water

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How many non metals are there in benzoic acid?

Oxana [17]

Answer:

There are 3 non-metals in benzoic acid.

Explanation:

They are Hydrogen, Oxygen, and Carbon.

6 0

3 years ago

6) Given that the density of olive oil is 0.92 g/mL, calculate the followin a. The mass of 20.0 mL of olive oil. The volume of 2

fgiga [73]

We are given:

Density of Olive oil = 0.92 g / mL

Mass of 20 mL Olive oil:

We know that the density = 0.92 grams / mL

multiplying the numerator and the denominator by 20

Density = 0.92 * 20 grams / 20 mL

Density = 18.4 grams / 20 mL

So, we have 18.5 grams in 20 mL of Olive oil

Volume of 20 grams Olive oil:

We need to multiply the numerator and the denominator of density by a number, that when multiplied by 0.92 will give 20

let that number be x:

0.92 * x = 20

x = 20/0.92

x = 21.74 (approx)

Multiplying the numerator and the denominator by x:

Density = 0.92 grams / 1 mL

Density = 0.092 * 21.74 / 21.74 mL

Density = 20 grams / 21.74 mL

So, we can see that 20 grams of the oil will have the volume 21.74 mL

4 0

3 years ago

HELPPPPPP Calculate the frequency of light with a wavelength 559nm

Alchen [17]

Answer:

Refer to the attachment

5 0

3 years ago

Iodine, I2, has many uses, including the production of dyes, antiseptics, photographic film, pharmaceuticals, and medicinal soap

svetoff [14.1K]

Answer:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.

Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

Explanation:

Oxidation-reduction reaction is the simulaneous oxidation and reduction of the substances and is represented by two half-reactions.

The oxidation half-reaction is the loss of electrons, with the consequent increase in the oxidation state by the oxidized substance.

In this case, the process that shows the loss of electrons is:

2I⁻ → I₂ + 2e⁻

That reaction shows:

Two I⁻ ions lose two electrons (one each) to be oxidized to I₂.

The change in the oxidation number is from -1 to 0.

Hence this half-reaction is the oxidation reaction.

On the other hand, the reduction half-reaction is the gain of electrons, with the consequent reduction of the oxidation state by the reduced substance.

In this case, the process that shows the gain of electrons is:

Cl₂ + 2e⁻ → 2Cl⁻

That reaction shows:

Two Cl atoms gain two electrons (one each) to be reduced to Cl⁻.

The change in the oxidation number is from 0 to - 1.

Hence, this half-reaction is the reduction reaction.

Summary:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.

Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

4 0

3 years ago

Suppose that 27 g of each of the following substances is initially at 29.0 ∘C. What is the final temperature of each substance u

Leviafan [203]

Answer:

The answer is going to be GOLD

5 0

3 years ago