1) Convert 12.9 liters of Oxygen to mol at the given conditions:
PV = nRT ⇒ n = PV/RT
n = [1.2atm*12.9 l] / [0.082 atm l /K mol * 297K]
n = 0.636 mol of O2
2) use the stoichiometry derived from the balanced chemical equation
1mol C2H4 / 3 mol O2 = x mol C2H4 / 0.636 mol O2
x = 0.636 / 3 mol O2 = 0.212 mol O2.
Answer: 0.212 mol O2
Answer:
There are 23076 peanut M&M's in 53.768 kg of M&M's.
Explanation:
First we <u>convert 53.768 kg into g</u>:
- 53.768 kg * 1000 = 53768 g
Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:
So there are 23076 peanut M&M's in 53.768 kg of M&M's.
A. 0.02 mol of O2
B. 0.1 mol of CI2
C. 1 mol of N2
D. 2 mol of H2
Bolded answer is correct.
Answer: Charles's law, Avogadro's law andd Boyle's law.
Charles law states the constant ratio of volume to temperature, at constant pressure. Boyle's law states the constat product of pressure and volumen at constant temperature. Avogadro's law states that equal volumes of gases at the same temperature and pressure have equal number of particles.
So, all those three laws combined state the relation of pressure, volume, temperature and number of particles of a gas, which is what the ideal gas law does: PV = n RT.
