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vitfil [10]
3 years ago
12

How many moles of HCl would react with 37.1 mL of 0.138 M Sr(OH)2

Chemistry
1 answer:
Lena [83]3 years ago
5 0

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl(aq) + Sr(OH)₂ → SrCl₂(aq) + 2H₂O(l).

V(Sr(OH)₂) = 37.1 mL ÷ 1000 mL/L.

V(Sr(OH)₂) = 0.0371 L; volume of the strontium hydroxide solution.

c(Sr(OH)₂) = 0.138 M; molarity of the strontium hydroxide solution.

n(Sr(OH)₂) = c(Sr(OH)₂) · V(Sr(OH)₂).

n(Sr(OH)₂) = 0.0371 L · 0.138 mol/L.

n(Sr(OH)₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n(Sr(OH)₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(Sr(OH)₂).

n(HCl) = 2 · 0.0051 mol.

n(HCl) = 0.0102 mol; amount of the hydrochloric acid.

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Answer:

The value is  K  =  8*10^{61}

Explanation:

From the question we are told that

    The equation is  2 Cr  +  3Pb^{2+} \to 3Pb + 2Cr^{3+}

     The  temperature is  T = 25^oC =  298 K   [room  \ temperature ]

     The  emf at standard condition is  E^o_{cell}  =  0.61 \  V

Generally at the cathode

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Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  

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Here  n  is  the no of electron  with value n = 6

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  =>   G =  6  * 96487 *  0.61

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This Gibbs free energy can also be represented mathematically as

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=>  K  =  antilog^{\frac{G}{ RT} }

Generally  antilog =  2.718

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=>   K  =  8*10^{61}

       

         

       

         

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3 years ago
How many atoms are in 2.70 moles of iron (Fe) atoms?
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3 0
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Calculate the energy required to melt 21 g of ice at 0 oC.
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<u>We are given:</u>

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Energy = 7.02 kJ OR 7020 joules

7 0
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