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3 years ago

15 yards to 18 yards increase or decrease

Mathematics

2 answers:

posledela3 years ago

8 0

<span>From 15 yards to 18 yards there is an increase of 3.

Answer: increase</span>

dlinn [17]3 years ago

3 0

This is an increase of 3 yards.

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A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

kiruha [24]

(a) after t minutes

If $y(t)$ is the amount of salt (in kg) after $t$ minutes, then $y(0) = 0 \ (pure\ water)$ and the total amount of liquid in the tank remains constant at 1000 L.

$\displaystyle \frac{dy}{dt} \\ = \left( 0.05 \frac{\text{kg}}{\text{L}} \right) \left( 5 \frac{\text{L}}{\text{min}} \right) + \left( 0.04 \frac{\text{kg}}{\text{L}} \right)\left( 10 \frac{\text{L}}{\text{min}} \right) - \left( \frac{y(t)}{1000} \frac{\text{kg}}{\text{L}} \right)\left( 15\frac{\text{L}}{\text{min}} \right) \\ \\ 
= 0.25 + 0.40 - 0.015y = 0.65 - 0.015 y = \frac{130 - 3y}{200} \frac{\text{kg}}{\text{min}}$

$\text{Hence, } \displaystyle \int \frac{dy}{130 - 3y} = \int\frac{dt}{200}$

and $-\frac{1}{3}\ln|130 - 3y| = \frac{1}{200}t + C.$

Because $y(0) = 0$ , we have $-\frac{1}{3} \ln 130 = C$

so

$-\frac{1}{3}\ln|130 - 3y| = \frac{1}{200}t -\frac{1}{3} \ln 130\ \Rightarrow \\ \\\ \ln|130 - 3y| = -\frac{3}{200}t + \ln 130 \ \Rightarrow \\ \\ |130 - 3y| = e^{-3t/200 + \ln 130} \ \Rightarrow \\ \\
|130 - 3y| = 130e^{-3t/200}$

Since $y$ is continuous, $y(0) = 0$ , and the right-hand side is never zero, we deduce that $130 - 3y$ is always positive.

Thus, $130 - y = 130e^{-3t/200}$ and
$y = \frac{130}{3}\left( 1 - e^{-3t/200}\right) \text{ kg}$

(b)

After one hour,

$y = \frac{130}{3}\left( 1 - e^{-3 \cdot 60/200}\right) = \frac{130}{3}(1 - e^{-0.9} ) \approx 25.7 \text{ kg}$

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3 years ago

What is 8 divided by 0.24

natulia [17]

The answer is 33.3333

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3 years ago

Read 2 more answers

G = -5r + 13<br> what does g equal to

hram777 [196]

Answer:

go to cymath and put your problem in their

Step-by-step explanation:

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3 years ago

A= 12b1+b2h ; solve for b1

slega [8]

Answer:

b1 = 0, b2 = 0

EXPLICACION

A = 12 b1 + b2 h

A - 12 b1 - b2 h = 0

b2!=0, h = -(12 b1)/b2

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3 years ago

Week 5 Quiz - Saving (15pts) 1. If the interest rate on a savings account is 0.01%, approximately how much money do you need to

LenaWriter [7]

In order to calculate the minimum amount required, we will first round the below-minimum-balance fee to $10. Next, we will use the equation:
A = I * (IR)^n, where A is the amount after n years and I is the initial investment and IR is the interest rate per year.
10 = I*(0.0001)^1
I = $100,000
$100,000 must be in the account to cover the minimum fees.

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3 years ago