15 yards to 18 yards increase or decrease

Mathematics

2 answers:

posledela3 years ago

8 0

<span>From 15 yards to 18 yards there is an increase of 3.

Answer: increase</span>

dlinn [17]3 years ago

3 0

This is an increase of 3 yards.

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3- A rectangle has an area of 30 square meters arm a perimeter of 34 meters the dimensions , of the rectangle I 9 , a J v ft HA

Leto [7]

If you are looking for the answer to the question above you have to ask yourself what two numbers multiply to 30 and equal 17 when added up. We halve the perimeter to make this easier. So your answer is 15 and 2 because 15 *2=30. If the sides are 15 and 2 then, 15(2) +2(2)=34. There is your answer.

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3 years ago

Form a polynomial using numbers -4,4,2 with a degree of 3

shtirl [24]

These three roots are sufficient to enable us to form a 3rd degree polynomial:

f(x) = (x+4)(x-4)(x-2) = (x^2 - 16)(x-2) = x^3 - 2x^2 - 16x + 32 (answer)

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3 years ago

How do you make 1 1-2/1-6-7/8 a mixed number

AveGali [126]

Answer:

17/8

Step-by-step explanation:

2/1=2

11-2-6-7/8

9-6-7/8

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3 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$