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makkiz [27]
4 years ago
13

15 yards to 18 yards increase or decrease

Mathematics
2 answers:
posledela4 years ago
8 0
<span>From 15 yards to 18 yards there is an increase of 3.

Answer: increase</span>
dlinn [17]4 years ago
3 0
This is an increase of 3 yards.
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What is the distance between the points (4,3) and (1,-1) on the coordinate
frozen [14]

Answer:

The distance between the points (4,3) and (1,-1) is C. 5 units.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If 3x+13= 19, find the value of 4x +1
12345 [234]

Answer:

It would be 8

Step-by-step explanation:

It would be six because 13 plus 3 is 16 and the answer was 19 so I added 3 more and I got 19. So that made me think that the value of x is 3. :)

6 0
3 years ago
If the set U = {all positive integers} and set A = {x|x ∈ U and x is an odd positive integer}, which describes the complement of
dlinn [17]

Answer: Choice D) set of even integers

=======================================================

Explanation:

U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}

A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}

A^c = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}

A^c = {set of even numbers from set U}

In set theory, the complement is simply the complete opposite. If the number 7 is found in set A for instance, then 7 is not going to live in the complement A^c

The opposite of the odd numbers is the set of even numbers.

Therefore, we go for <u>choice D</u> as our final answer.

Side note: if we union set A with its complement A^c then we get the universal set as a result. A \cup A^c = \text{universal set} = \text{set of all positive integers}

5 0
3 years ago
How many picture would you draw if 12 students chose game shows as their favorite kind of TV show?
Leya [2.2K]
The answer will be 12
3 0
3 years ago
Solve for X
sweet-ann [11.9K]

Answer:

x = 1035 = MXXXV

Step-by-step explanation:

<u>Roman Numbers </u>

It's an ancient number system developed in Rome where numbers are represented by the letters {I,V,X,L,C,D,M}. The value of each are, respectively {1,5,10,50,100,500,1000}. If some letter is repeated, then it's value must be multiplied by the number of times the letter is present. For example, XXVII has two X's and two I's, so the conversion is 10+10+5+1+1=27.

If a less-valued letter appears before a greater one, it subtracts. For example CDI=-100+500+1=401

Our numbers are

MMMMMMMMCDXV=8*1000-100+500+10+5=8415

MDCCCLXIII = 1000+500+300+50+10+3=1863

DLXI = 500+50+10+1=561

XXVII = 20+5+2=27

We now operate in our numerical system

\displaystyle x = \frac{MMMMMMMMCDXV * MDCCCLXIII}{DLXI * XXVII}

\displaystyle x = \frac{8415 * 1863}{561 * 27}

\displaystyle x = \frac{15677145}{15147}

\displaystyle x = 1035

Converting back to roman

\boxed{\displaystyle x = MXXXV}

3 0
3 years ago
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