A 200 ohm resistor has a 2-ma current in it. what is the voltage across the resistor?
1 answer:
Answer:
V=4v
Explanation:
To perform this operation, we will refer to Ohm's Law. This Law relates the terms current, voltage and resistance.
<em>The current intensity that passes through a circuit is directly proportional to the voltage or voltage of the circuit and inversely proportional to the resistance it presents.</em>
Where
I=Current
V= Voltage
R=Resistance.
So, in this case:
R=200 ohm
I= 2mA = 0.002 A
V= searched variable
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Answer:
(1) 2.05 x 10^4 N/C
(2) Downward
(3) upward, 9.8 m/s^2
(4) upward, 9.8 m/s^2
Explanation:
q = - 2.1 micro coulomb, m = 0.0044 kg, g = 9.8 m/s^2
(1) The electric force is given by F = - q x E
The magnitude of electric force is balanced by the weight of the charged particle
q x E = m x g
E = mg / q
E = 2.05 x 10^4 N/C
(2) As the electric force is acting upward and the weight is downward so the elecric field is in downward direction.
(3) The charge is doubled,
then the electric field becomes half.
E = 2.05 x 10^4 / 2 = 1.025 x 10^4 N/C
The direction is same that is in downward direction.
Acceleration = Force / mass
a = mg / m = 9.8 m/s^2 upward
(4) The charge is doubled,
then the electric field becomes half.
E = 2.05 x 10^4 / 2 = 1.025 x 10^4 N/C
The direction is same that is in downward direction.
Acceleration = Force / mass
a = mg / m = 9.8 m/s^2 upward