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ioda
3 years ago
13

Why might it be necessary to ignore some of the data points just before and just after the collision?

Physics
1 answer:
krek1111 [17]3 years ago
7 0
We have no idea. We need to examine the experimental set-up. You've given us no information, except that there may have been some sort of collision.
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A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of usi
atroni [7]

Answer:

\huge\boxed{\sf 1.6\ units = 14.4p}

Explanation:

Since,

<h3><u>1 kWh = 1 unit</u></h3>

So,

1.6 kWh = 1.6 units

If,

<h3>1 unit = 9p</h3>

1.6 units = 9p × 1.6

1.6 units = 14.4p

\rule[225]{225}{2}

8 0
1 year ago
4. A metal fork has a density of 7.8 g/cm ³. Is this fork made up of aluminum?
Morgarella [4.7K]
No, aluminum has a density near 2.7 g/cm^3 
<span>7.8 g/cm^3 is near the density of iron (or in the case of a fork, steel).
this is it

</span>
5 0
3 years ago
3.00 m^3 of water is at 20.0°C.
romanna [79]

Answer:

\triangle V = 0.02484m^3

Explanation:

Given

V_1 = 3.00m^3 --- initial volume

T_1 = 20.0^oC --- initial temperature

T_2 = 60.0^oC --- final temperature

\gamma = 207*10^{-6 ---  coefficient of thermal expansion:

Required

The change in volume

To do this, we make use of cubic expansivity formula

\triangle V = \gamma * V_2 * (T_2 - T_1)

So, we have:

\triangle V = 207 * 10^{-6} * 3.00 * (60.0 - 20.0)

\triangle V = 207 * 10^{-6} * 3.00 * 40.0

\triangle V = 0.02484m^3

The volume will expand by 0.02484m^3

7 0
2 years ago
A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg
motikmotik

Answer:

\omega_{f}=1.634\ rad/s  

Explanation:

given,  

diameter of merry - go - round = 2.40 m  

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg  

initial angular momentum of the system  

L_i = I\omega_i  

L_i =356\times 1.80  

L_i =640.8\ kg.m^2/s  

final angular momentum of the system  

L_f = (I_{disk}+mR^2)\omega_{f}  

L_f = (356 + 25\times 1.2^2)\omega_{f}  

L_f= (392)\omega_{f}  

from conservation of angular momentum  

L_i = L_f  

640.8= (392)\omega_{f}  

\omega_{f}=1.634\ rad/s  

8 0
2 years ago
Read 2 more answers
PLEASE HELP!!!! i will give brainliest to the first person...
ExtremeBDS [4]

Answer: Fossil fuels power the machine that shakes the tree so the apples fall to the ground

Explanation: most machines are powered by fossil fuels

8 0
3 years ago
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