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SVEN [57.7K]
3 years ago
13

Given the molar specific heat cv of a gas at constant volume, you can determine the number of degrees of freedom s that are ener

getically accessible. for example, at room temperature cis-2-butene, c4h8, has molar specific heat cv=70.6jmol⋅k. how many degrees of freedom of cis-2-butene are energetically accessible?
Chemistry
2 answers:
Ksju [112]3 years ago
8 0
The molar specific heat Cv = R s / 2
70.6 J/mol.K = (8.314 J/mol.K) * s / 2
So the number of degrees of freedom are:
s = 16.98 = 17
andrew11 [14]3 years ago
4 0

The correct answer is 17

The explanation:

To get how many degrees of freedom of Cis-2-butene we are going to use this formula of the molar specific heat:

Cv = R.s / 2

when Cv is the molar specific heat = 70.6 J/mol.K

and R is the ideal gas constant = 8.314 J/mol.K

and S is the degrees of freedom of cis-2-butene : it is the number of independent coordinates to specify the motion of a molecule.

so by substitution:

70.6 J/mol.K = [8.314 J/mol.K] * s / 2

So, the number of degrees of freedom = s = 16.98 ≈ 17

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Determine the limiting reactant (lr) and the mass (in g) of nitrogen that can be formed from 50.0 g n2o4 and 45.0 g n2h4. some p
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1) to calculate the limiting reactant you need to pass grams to moles.
<span> moles is calculated by dividing mass by molar mass
</span>
mass of N2O4: 50.0 g 
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</span><span>molar mass of N2H4 = 32.05 g/mol.
</span>mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of <span><span>N2H4

</span> 2)</span>
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react  0,54 moles of N2O4, you need 2x0,54 moles of <span>N2H4 moles
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You have more that 1,08 moles </span><span>N2H4, so this means the limiting reagent is not N2H4, it's </span>N2O4. The molecule that has molecules that are left is never the limiting reactant.

3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
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4) the only thing left to do is convert the moles obtained, to grams.
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1,62 mol of N2= mass/ 28
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