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Ipatiy [6.2K]
3 years ago
12

An atom of the element iron has an atomic number of 26 and an atomic mass number of 56. if it is neutral, how many protons, neut

rons, and electrons does it have?
Chemistry
2 answers:
allsm [11]3 years ago
6 0
<span> 26 protons, 30 neutrons, 26 electrons</span>
asambeis [7]3 years ago
6 0

Answer:

26 protons, 26 electrons, 30 neutrons

Explanation:

Let P = protons, N = neutrons, E = electrons

The mass number of an atom is the sum of protons and neutrons in the nucleus of the atom.

The number of neutrons is the difference between the mass and atomic numbers of the atom

Therefore, 56 = P + N

where N = 56 - 26

N = 30

That means the number of neutrons is 30

To find P, 56 = P + N, N being 30

56 is now P + 30

56 = P + 30

56 - 30 = P

P = 26

Now, for an atom in its neutral state, the number of electrons is equal to the number of protons

Therefore, E is also 26

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D. Making the reactant particles larger
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How many moles of O2 are required to generate 18 moles of H2O in the given reaction? 2C8H18 + 25O2 16CO2 + 18H2O
Veronika [31]
There's a slight error in your equation. I think you were trying to present it like this:

2C8H18 + 25O2 -> 16CO2 + 18H2O

Mole Ratio
O2 : H20
25 : 18
? moles : 18 moles
(18/18)×25 : 18 moles

25 moles : 18 moles

Final answer would be 25 moles of O2. :)

If you have any doubts that you want to clarify with me, please ask me! :)
I will do my utmost best to help you.
7 0
3 years ago
Read 2 more answers
Balance the following equation:
Sonbull [250]
You only need a 2 at the end In front of the NaCl
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2 years ago
Can someone do this for me i wasent there when we learned it
Anna11 [10]
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4 0
3 years ago
The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
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