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Anna11 [10]
2 years ago
8

Help!!!

Chemistry
2 answers:
Paha777 [63]2 years ago
7 0

那是因为我很笨,我不知道,但无论如何

Explanation:

ok

Margarita [4]2 years ago
6 0

Answer:

The answer is: The mass number remains the same, and the atomic number decreases by one.

The rest of the assignment:

Polonium has a large, unstable nucleus. Through which process is it most likely to become stable?

gamma decay

beta-plus decay

beta-minus decay

alpha decay(✔️)

Which type of energy does alpha decay generate?

Potential

Sound

Electromagnetic

kinetic(✔️)

Use the equation to answer the question.

14 6C→14 7N+ 0−1e

Which type of radioactive decay does the equation model?

alpha decay

beta-minus decay(✔️)

beta-plus decay

gamma decay

How does the nucleus change in beta-plus decay?

The mass number decreases by one, and the atomic number remains the same.

The mass number remains the same, and the atomic number decreases by one(✔️)

The mass number remains the same, and the atomic number increases by one.

The mass number increases by one, and the atomic number remains the same.

An unstable nucleus undergoes gamma decay. How does the nucleus change?

It becomes less stable by repositioning its particles.

It becomes more stable by emitting energy and particles.

It becomes more stable by repositioning its particles(✔️)

It becomes less stable by emitting energy and particles.

Hope this helps

Explanation:

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You're looking for the number of moles of H2, and you have 6.0 mol Al and 13 mol HCL.

For the first part, you have to make your way from 6.0 mol of Al to mol of H2, right? For that to happen, you need to make a conversion factor that will cancel the mol Al, in such case use the 2 moles of Al from your equation to cancel them out. At the top of the equation, you can use the number of moles of H2 from the equation and find the moles that will be produced for the H2.

6.0mol Al x 3 mol H2/2 mol Al = 9 mol H2

For the second part, you have to make the same procedure, make a conversion factor that will cancel the mol of HCL and for that you need to use the 6 mol HCL from your equation, and at the numerator you can put the 3 mol of H2 from the equation so that you can find the number of moles of H2 that will be produced.

13 mol HCL x 3 mol H2/6 mol HCL = 6.5 mol H2

As it can be seen, HCL produces the less amount of H2 moles. Therefore, the reaction CANNOT produce more than 6.5 mol H2, in that case 6.5 mol will be the maximum number of moles that will be produced at the end because HCL does not have enough to produce more than 6.5 mol.

In that case HCL is the limiting reactant because it limits that will be produced, and so the answer is B!

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We are already given the equations and their corresponding deltaH. Using Hess' Law, we can generate this equation:
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Explanation:

Data obtained from the question include:

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Molarity is simply defined as the mole of solute per unit litre of the solution. It is represented mathematically as:

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With the above formula, we can obtain the volume of the solution as follow:

Molarity = mole /Volume

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2.25 x volume = 4.58

Divide both side by 2.25

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