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3 years ago

Find the surface area of the composite solid.

Mathematics

1 answer:

Scilla [17]3 years ago

4 0

Answer with Step-by-step explanation:

The given figure is a cuboid.

We know that surface area(S) of cuboid is given by:

S=2(lb+bh+hl)

Where l is the length, b is the breath and h is the height

Here, l=12 mm

b=6 mm

and h=(7+2) mm=9 mm

Surface Area= 2(12×6+6×9+9×12)

=2(72+54+108)

= 2×234

= 468 mm²

Hence, Correct option is:

C. 468 mm squared

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In the data set below, what is the upper quartile?

Bingel [31]

77 is the upper quartile. middle number between the half way mark and highest number.

5 0

3 years ago

Rita Hangs a picture frame of with 22 cm on the wall the distance from the nail to the top edge of the picture frame is 8 cm she

DiKsa [7]

Answer: Yes, Rita has enough wire to hang the picture frame.

Step-by-step explanation:

Since we have given that Rita hangs a picture frame of width 22 cm on the wall , the distance from the nail to the top edge of the picture frame is 8 cm, and she has 26 cm of wire to hang the picture .

She need wire only to hang the picture frame which 8 cm away from the nail, and she has 26 cm of wire to hang it .

And 26 > 8 i.e. 26 is greater than 8.

So, Rita has enough wire to hang the picture frame .

3 0

3 years ago

A pole that is 3.5m tall casts a shadow that is 1.47m long. At the same time, a nearby tower casts a shadow that is 42.75m long.

Stells [14]

<u>Answer:</u>

The height of the tower nearby the pole is 102 m.

<u>Solution:</u>

Given,

Height of the pole = 3.5 m

Length of the shadow of the pole = 1.47 m

Length of the shadow of the tower nearby = 42.75 m

Let us assume the height of the tower as x

$\frac{height of the pole}{length of the shadow of the pole}=\frac{height of the tower}{length of the shadow of the tower}$

$\frac{3.5}{1.47} = \frac{x}{42.75}$

On solving for x we get,

$x = \frac{3.5}{1.47}\times 42.75$

$x = 101.785 m$

On rounding off to the nearest meter we get,

x=102 m

$\therefore$ The height of the tower is 102 meter.

7 0

3 years ago

#4 home do I find which one it is?

lina2011 [118]

$\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}$

$\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}$

for example, let's look at the first set

y+3x =5 or y = -3x+ 5
and y = -3x + 2
y = m + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution

8 0

4 years ago

Choose the correct symbol to form a true statement. 11/18 ____5/9

Alinara [238K]

For this case we have the following numbers:

$\frac {11} {18} = 0.611111111111\\\frac {5} {9} = 0,555555555556$