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Ipatiy [6.2K]
3 years ago
13

Radioactive carbon, or C-14, is used to date fossil remains. When C-14 decays, as seen in the nuclear equation, it produces what

nuclide of nitrogen? A) N-7 B) N-13 C) N-14 D) N-15
Physics
2 answers:
olga nikolaevna [1]3 years ago
7 0
The reaction of radiodecay of carbon C-14 is
C-14 --> N-14 + e- + (ve)
where e- is an electron and (ve) is an electron-type antineutrino.
Basically, when the carbon nucleus (atomic number: 6, mass number: 14) decays, a neutron of the nucleus converts into a proton (therefore, the mass number remains the same, 14, but the atomic number increases by 1, therefore it becomes nitrogen) and releases an electron-antineutrino pair. 

So, the correct answer is C), N-14.
jekas [21]3 years ago
6 0

Answer:

the answer is c

Explanation:

i did it on usatestprep

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List 5 differences between a compound and an element.
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Answer:

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5 0
3 years ago
Problem 3.2 Part A Draw the vector C⃗ =A⃗ +B⃗ .(Figure 1)
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A cell is classified as eukaryotic if the cell
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3 years ago
Read 2 more answers
A hot-air balloon is rising upward with a constant speed of 2.51 m/s. When the balloon is 3.16 m above the ground, the balloonis
icang [17]

Answer:

  t = 1.099 s

Explanation:

given,

constant speed = 2.51 m/s

height of balloon above ground = 3.16 m

time elapsed before it hit the ground = ?

Applying equation of motion to the compass

y = u t + \dfrac{1}{2}at^2

-3.16 = 2.51 t + \dfrac{1}{2}\times (-9.8)t^2

4.9 t^2 - 2.51 t - 3.16 = 0

using quadratic formula to solve the equation

t = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

t = \dfrac{-(-2.51)\pm \sqrt{2.51^2-4(4.9)(-3.16)}}{2\times 4.9}

  t = 1.099 s, -0.586 s

hence, the time elapses before the compass hit the ground is equal to 1.099 s.

8 0
3 years ago
A series R-L-C circuit is connected to a 70.0 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 80.0 Ω and a
Andreyy89

Answer:

62.7 VA

Explanation:

The apparent power (power supplied by the source) of an AC circuit is determined by

S = \frac{(Vrms)^2}{Z}

The impedance(Z) depends on the frequency, but in this case it is given to us that it is 102 ohms at this frequency.

So:

S = \frac{(80 V)^2}{102 \Omega} = 62.7 VA

3 0
3 years ago
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