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Alja [10]
2 years ago
10

This diagram shows the forces acting on a car. The center dot represents the car, a the arrows represent the forces acting on th

e car. Values are given for each of the forces. Refer to the diagram to answer the question. How can the forces acting on the car be described?
A:Balanced

B:Inertial

C:Unbalanced

D:Buoyant​
Physics
1 answer:
mylen [45]2 years ago
5 0
Need diagram right? Post it
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A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º. What is the coefficient of
Alex_Xolod [135]

Given :

A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.

To Find :

The coefficient of static friction between the box and the plane.

Solution :

Vertical component of force :

mg\ sin\ \theta =  120\times 10 \times sin\ 47^\circ{}=877.62 \ N

Horizontal component of force(Normal reaction) :

mg\ cos\ \theta =  120\times 10 \times cos\ 47^\circ{}=818.40 \ N

Since, box is on the verge of slipping :

mg\ sin\ \theta= \mu(mg \ cos\ \theta)\\\\\mu = tan \ \theta\\\\\mu = tan\ 47^o\\\\\mu = 1.07

Therefore, the coefficient of static friction between the box and the plane is 1.07.

Hence, this is the required solution.

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Find the below attachment

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